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jeka57 [31]
3 years ago
10

Explain how to determine the number of neutrons an

Chemistry
2 answers:
oee [108]3 years ago
5 0
To find the neutrons you add the mass number and the atomic number for neutrons


Hope this helps


-Zayn Malik
Viktor [21]3 years ago
5 0

Answer:

mass number - atomic number

Explanation:

mass number = number of proton + number of neutron

atomic number = number of proton

<em />

<em />

<em>hope it helps</em>

<em />

<em />

<em>please mark as brainliest</em>

<em>Darrell cares</em>

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C4H10 is an example of a (n) a. Molecular formula b. Structural formula c. Atomic formula d. Geometric formula​
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Explanation:

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The solubility of KNO3(s) in water increases as the..
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The answer would be b. Temperature of the solution increases 

Temperature determines the kinetic energy of the water molecule. Higher temperature will cause the molecule to moves faster and the compound (KNO3) could break solute molecule easier make it become more soluble. A higher pressure will increase the solubility of a gas, not solid


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What is pyruvic acid changed into in lactic acid fermentation
myrzilka [38]

Answer:

pyruvic acid changes to alcohol and carbon dioxide.

Explanation:

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7 0
3 years ago
Identify a reason that chemical reactions release energy during the reaction process.
Bess [88]

Answer:

option b

Explanation:

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5 0
3 years ago
Read 2 more answers
If you combine 230.0 mL 230.0 mL of water at 25.00 ∘ C 25.00 ∘C and 120.0 mL 120.0 mL of water at 95.00 ∘ C, 95.00 ∘C, what is t
Thepotemich [5.8K]

<u>Answer:</u> The final temperature of the mixture is  49°C

<u>Explanation:</u>

To calculate the mass of water, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

  • <u>For cold water:</u>

Density of cold water = 1 g/mL

Volume of cold water = 230.0 mL

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{230.0mL}\\\\\text{Mass of water}=(1g/mL\times 230.0mL)=230g

  • <u>For hot water:</u>

Density of hot water = 1 g/mL

Volume of hot water = 120.0 mL

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{120.0mL}\\\\\text{Mass of water}=(1g/mL\times 120.0mL)=120g

When hot water is mixed with cold water, the amount of heat released by hot water will be equal to the amount of heat absorbed by cold water.

Heat_{\text{absorbed}}=Heat_{\text{released}}

The equation used to calculate heat released or absorbed follows:

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c\times (T_{final}-T_1)=-[m_2\times c\times (T_{final}-T_2)]      ......(1)

where,

q = heat absorbed or released

m_1 = mass of hot water = 120 g

m_2 = mass of cold water = 230 g

T_{final} = final temperature = ?°C

T_1 = initial temperature of hot water = 95°C

T_2 = initial temperature of cold water = 25°C

c = specific heat of water = 4.186 J/g°C

Putting values in equation 1, we get:

120\times 4.186\times (T_{final}-95)=-[230\times 4.186\times (T_{final}-25)]

T_{final}=49^oC

Hence, the final temperature of the mixture is  49°C

4 0
3 years ago
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