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Alik [6]
3 years ago
11

Rank the following species according to the decreasing energy needed to raise the temperature of 10.0 g of the substance by 25.0

∘C.
Rank from most to least energy needed. To rank items as equivalent, overlap them.
Chemistry
1 answer:
bonufazy [111]3 years ago
6 0

Answer 1) : To rank the species according to the decreasing energy needed to raise the temperature of 10 g of the substance by 25 °C, the oder of energy needed is given below as per their specific heat.

Which requires more energy as per their specific heats;

  1. water  4.184
  2. aluminum  0.897
  3. cast iron  0.460
  4. Copper  0.385
  5. Silver 0.235

Answer 2)To rank items as equivalent, overlap them.

The average kinetic energy of the molecules after point D,

The average kinetic energy of the molecules from point B to point C,

The average kinetic energy of the molecules before point A.

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There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In
adell [148]

Answer:

The net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide is 523.2 kJ.

Explanation:

Step 1:

CaC_2(s) + 2H_2O(g)\rightarrow C_2H_2(g) + Ca(OH)_2(s),\Delta H_1=414.0 kJ...[1]

Step 2 :

6C_2H_2(g) + 3CO_2(g) + 4H_2O(g)\rightarrow 5CH_2CHCO_2H(g) \Delta H_2=132.0kJ..[2]

Adding 6 × [1] and [2]:

6CaC_2(s) + 12H_2O(g)\rightarrow 6C_2H_2(g) + 6Ca(OH)_2(s)

6C_2H_2(g)+3CO_2(g)+16H_2O(g)\rightarrow 5CH_2CHCO_2H(g)

we get :

6CaC_2(s) + 8H_2O(g)+3CO_2(g)\rightarrow 5CH_2CHCO_2H(g)+ 6Ca(OH)_2(s),\Delta H'=?

\Delta H'=6\times \Delta H_1+\Delta H_2

\Delta H'=6\times 414.0 kJ+132.0kJ

\Delta H'=2,626 kJ

Energy released on formation of 5 moles of acrylic acid = 2,626 kJ

Energy released on formation of 1 mole of acrylic acid:

\frac{ 2,626 kJ}{5 } = 523.2 kJ

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Yes.

Explanation:

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