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Alik [6]
3 years ago
11

Rank the following species according to the decreasing energy needed to raise the temperature of 10.0 g of the substance by 25.0

∘C.
Rank from most to least energy needed. To rank items as equivalent, overlap them.
Chemistry
1 answer:
bonufazy [111]3 years ago
6 0

Answer 1) : To rank the species according to the decreasing energy needed to raise the temperature of 10 g of the substance by 25 °C, the oder of energy needed is given below as per their specific heat.

Which requires more energy as per their specific heats;

  1. water  4.184
  2. aluminum  0.897
  3. cast iron  0.460
  4. Copper  0.385
  5. Silver 0.235

Answer 2)To rank items as equivalent, overlap them.

The average kinetic energy of the molecules after point D,

The average kinetic energy of the molecules from point B to point C,

The average kinetic energy of the molecules before point A.

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It's B) electrons, is the right answer

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4 years ago
How many moles are in 64.8 g of ZnCl ?
ivann1987 [24]

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at least 1

Explanation:

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3 years ago
Draw the product formed when the following diene is treated with one equivalent of HCl. Do not show stereochemistry in your answ
garri49 [273]

Answer:

4-chloro-4-methyl-cyclohexene.

Explanation:

Hello,

On the attached picture you will find the chemical reaction forming the required product, 4-chloro-4-methyl-cyclohexene. In this case, according to the Markovnicov’s rule, it is more likely for the chlorine to be substituted at the carbon containing the methyl radical in addition to the hydrogen to the next carbon to break the double bond and yield the presented product.

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6 0
3 years ago
Bleach contains the active ingredient NaClO. Analysis of bleach involves two sequential redox reactions: First, bleach is reacte
Alisiya [41]

Answer:

0,31%

Explanation:

For the reaction:

I₂ + 2 S₂O₃²⁻ → 2 I⁻ + S₄O₆²⁻

0,043 L × 0,117 M of sodium tiosulfate = 5,031x10⁻³ moles of S₂O₃²⁻

5,031x10⁻³ moles of S₂O₃²⁻ × \frac{1 I_2 mol}{2 S_{2}O_3 mol^{2-}} = <em>2,5156x10⁻³ moles of I₂</em>

These moles of I₂ were produced from:

ClO⁻⁻ + 2 H⁺ + 2 I⁻ → I₂ + Cl⁻ + H2O

2,5156x10⁻³ moles of I₂ ≡ moles of NaClO

2,5156x10⁻³ moles of NaClO ×\frac{74,44 g}{1mol} =<em> 0,187 g of NaClO</em>

Thus, percentage composition by mass is:

\frac{0,187 g of NaClO}{60 g Of Bleach} x 100 =<em> 0,31%</em>

I hope it helps!

5 0
3 years ago
10. A small helium tank claims to be able to fill 30 balloons to a volume of 3.15 L
Sindrei [870]

Taking into account the Boyle's law, 3.377 L of helium the tank will be able to  produce at a pressure of 94.2 kPa.

The gas laws are a set of chemical and physical laws that allow determining the behavior of gases in a closed system. The parameters evaluated in these laws are pressure, volume, temperature, and moles.

Boyle's law is one of the gas laws that relates the volume and pressure of a certain quantity of gas kept at constant temperature.

This law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant. That is, if the pressure increases, the volume decreases; while if the pressure decreases, the volume increases.

Mathematically, Boyle's law states that the product of pressure and volume is constant:

P×V= k

Studying two different states, an initial state 1 and a final state 2, it is satisfied:

P1× V1= P2×V2

In this case, you know:

  • P1= 101 kPa
  • V1= 3.15 L
  • P2= 94.2 kPa
  • V2= ?

Replacing in Boyle's law:

101 kPa× 3.15 L= 94.2 kPa× V2

Solving:

V2=\frac{101 kPa x3.15 L}{94.2 kPa}

<u><em>V2= 3.377 L</em></u>

In summary, 3.377 L of helium the tank will be able to  produce at a pressure of 94.2 kPa.

Learn more:

brainly.com/question/4147359?referrer=searchResults

7 0
3 years ago
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