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Alik [6]
3 years ago
11

Rank the following species according to the decreasing energy needed to raise the temperature of 10.0 g of the substance by 25.0

∘C.
Rank from most to least energy needed. To rank items as equivalent, overlap them.
Chemistry
1 answer:
bonufazy [111]3 years ago
6 0

Answer 1) : To rank the species according to the decreasing energy needed to raise the temperature of 10 g of the substance by 25 °C, the oder of energy needed is given below as per their specific heat.

Which requires more energy as per their specific heats;

  1. water  4.184
  2. aluminum  0.897
  3. cast iron  0.460
  4. Copper  0.385
  5. Silver 0.235

Answer 2)To rank items as equivalent, overlap them.

The average kinetic energy of the molecules after point D,

The average kinetic energy of the molecules from point B to point C,

The average kinetic energy of the molecules before point A.

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How many miles of iron can be produced from 3.5 moles of Fe2O3 and 6.2 moles of CO
AlekseyPX

Answer:

4.13 moles of Fe.

Explanation:

Given data:

Moles of iron produced = ?

Moles of Fe₂O₃ = 3.5 mol

Moles of CO = 6.2 mol

Solution:

Chemical equation:

Fe₂O₃ +  3CO      →    2Fe + 3CO₂

Now we will compare the moles of iron with CO and Fe₂O₃.

                 Fe₂O₃        :         Fe

                      1             :          2

                  3.5             :         2/1×3.5 = 7 mol

                 CO              :          Fe

                   3               :            2

                 6.2              :        2/3×6.2 = 4.13 mol

The number of moles of iron produced by CO are less it will limiting reactant.

Thus, moles of iron formed in given reaction are 4.13 moles.

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3 years ago
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3 years ago
Given the following equation: 4 NH3 (g)5 O2 (g) >4 NO (g) + 6 H20 (I) How many moles of NH3 is required to react with 25.7 gr
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Answer:

0.6425 moles of NH_3 is required to react with 25.7 grams of O_2.

Explanation:

mas of oxygen gas = 25.7 g

moles of oxygengas = \frac{25.7 g}{32 g/mol}=0.8031 mol

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\frac{4}{5}\times 0.8031 mol=0.6425 mol of ammonia gas

0.6425 moles of NH_3 is required to react with 25.7 grams of O_2.

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