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Alik [6]
2 years ago
11

Rank the following species according to the decreasing energy needed to raise the temperature of 10.0 g of the substance by 25.0

∘C.
Rank from most to least energy needed. To rank items as equivalent, overlap them.
Chemistry
1 answer:
bonufazy [111]2 years ago
6 0

Answer 1) : To rank the species according to the decreasing energy needed to raise the temperature of 10 g of the substance by 25 °C, the oder of energy needed is given below as per their specific heat.

Which requires more energy as per their specific heats;

  1. water  4.184
  2. aluminum  0.897
  3. cast iron  0.460
  4. Copper  0.385
  5. Silver 0.235

Answer 2)To rank items as equivalent, overlap them.

The average kinetic energy of the molecules after point D,

The average kinetic energy of the molecules from point B to point C,

The average kinetic energy of the molecules before point A.

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How many grams of calcium nitrate are needed to make 3.30 L of a 0.10 M solution?
ki77a [65]
54.15 g
First you start out with the equation n=cv (n= moles, c=molarity, v= volume)
You’re going to multiply 0.10M by 3.30L to get an answer of 0.33 moles of Ca(NO3)2
From there you’re gonna convert the moles to grams to get your answer, first you have to find the molar mass of Ca(NO3)2
This can be done by finding adding the molar mass of each individual substance
The answer you should get for the molar mass is 164.1 g
From there just multiply the number of moles you calculated (0.33 mol) by the molar mass (164.1 g) and your answer is going to be 54.15 g Ca(NO3)2
6 0
3 years ago
if 1.386 g of mg ribbon combusts to form 2.309 g of oxide product, calculate the experimental mass percent of oxygen from this d
Pavlova-9 [17]

1.386 g of Mg ribbon combusts to form 2.309 g of oxide product. The mass percent of oxygen in the oxide is 40.0 %.

Let's consider the reaction for the combustion of Mg.

Mg + 1/2 O₂ ⇒ MgO

1.386 g of Mg combusts to form 2.309 g of MgO. We want to determine the mass of oxygen in MgO. According to Lavoisier's law of conservation of mass, matter is not created nor destroyed over the course of a chemical reaction. Then, the mass of Mg in the reactants is equal to the mass of Mg in MgO. The mass of the magnesium oxide is the sum of the masses of magnesium and oxygen. The <u>mass of oxygen in the oxide</u> is:

mMgO = mMg + mO\\mO = mMgO - mMg = 2.309 g - 1.386 g = 0.923 g

We can calculate the mass percent of O in MgO using the following expression.

\% O = \frac{mO}{mMgO} \times 100\% = \frac{0.923 g}{2.309g} \times 100\%  = 40.0 \%

You can learn more about mass percent here: brainly.com/question/14990953

3 0
1 year ago
Question 7 (2 points)
serg [7]

Answer:

C. decrease the velocity.

4 0
2 years ago
0.03÷0.35 what is it rounding at least 3 digits
strojnjashka [21]
0.0857
Rounding off to three digits
Since 7 is more than five you change it to 0 and add 1 to 5
A: 0.086
6 0
2 years ago
Question 6 of 10
Marta_Voda [28]

Answer:

B. A chemist

<em>Hope it's help :)</em>

5 0
3 years ago
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