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3 years ago

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A waste treatment pond is 50m long and 25m wide, and has an average depth of 2m.The density of the waste is 75.3 lbm/ft3. Calcul

ate the weight of the pond contents in lbf, using a single dimensional equation for your calculation.

1 answer:

weeeeeb [17]3 years ago

6 0

Answer:

The weight of the pond contents is 6,643,233.22 lbf

Explanation:

Weight = density × volume × acceleration due to gravity

density = 75.3lbm/ft^3 = 75.3lbm/ft^3 × 0.45359kg/1lbm × (3.2808ft/1m)^3 = 1206.14kg/m^3

volume = length×width×depth = 50m×25m×2m = 2500m^3

acceleration due to gravity = 9.8m/s^2

Weight = 1206.14×2500×9.8 = 29,550,430N = 29,550,430N × 1lbf/4.4482N = 6,643,233.22lbf

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The complete question is shown on the first uploaded image

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From the diagram we see that is

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$I_r = (I_1 + m_1 r_1^2) + (I_2 + m_2 r_2^2) +(I_3 + m_3 r_3^2)$

$I_r = (I_1 + m_1 |x_r - x_1|^2) + (I_2 + m_2 |x_r - x_2|^2) +(I_3 + m_3 |x_r - x_3|^2)$

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