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Shalnov [3]
3 years ago
12

A waste treatment pond is 50m long and 25m wide, and has an average depth of 2m.The density of the waste is 75.3 lbm/ft3. Calcul

ate the weight of the pond contents in lbf, using a single dimensional equation for your calculation.
Engineering
1 answer:
weeeeeb [17]3 years ago
6 0

Answer:

The weight of the pond contents is 6,643,233.22 lbf

Explanation:

Weight = density × volume × acceleration due to gravity

density = 75.3lbm/ft^3 = 75.3lbm/ft^3 × 0.45359kg/1lbm × (3.2808ft/1m)^3 = 1206.14kg/m^3

volume = length×width×depth = 50m×25m×2m = 2500m^3

acceleration due to gravity = 9.8m/s^2

Weight = 1206.14×2500×9.8 = 29,550,430N = 29,550,430N × 1lbf/4.4482N = 6,643,233.22lbf

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Answer:

True

Explanation:

5 0
2 years ago
If the head loss in a 30 m of length of a 75-mm-diameter pipe is 7.6 m for a given flow rate of water, what is the total drag fo
Stolb23 [73]

Answer:

526.5 KN

Explanation:

The total head loss in a pipe is a sum of pressure head, kinetic energy head and potential energy head.

But the pipe is assumed to be horizontal and the velocity through the pipe is constant, Hence the head loss is just pressure head.

h = (P₁/ρg) - (P₂/ρg) = (P₁ - P₂)/ρg

where ρ = density of the fluid and g = acceleration due to gravity

h = ΔP/ρg

ΔP = ρgh = 1000 × 9.8 × 7.6 = 74480 Pa

Drag force over the length of the pipe = Dynamic pressure drop over the length of the pipe × Area of the pipe that the fluid is in contact with

Dynamic pressure drop over the length of the pipe = ΔP = 74480 Pa

Area of the pipe that the fluid is in contact with = 2πrL = 2π × (0.075/2) × 30 = 7.069 m²

Drag Force = 74480 × 7.069 = 526468.1 N = 526.5 KN

3 0
3 years ago
What financial arguments could you use to justify your proposed
Gnoma [55]

The recommendation to segregate FLTs and the workers are as follows:-1)Reputation of warehouse:- To be in the market the reputation of warehouse should be good,it can only happen when the worker of that warehouse is happy with the management looks after worker external and internal affairs. There should be two pathways one for vehicle and other for walking in which both can’t use vice versa.2)High Profitability:- When there is no incident or accident happens between the FLTs and the workers in the warehouse then off course the worker will be regular at work then there will be high profit .3)Insurance premium:- If there is zero accident happens in the ware house then there will no claim, the company will be in the profit..

7 0
2 years ago
malott, m. e. (2003). paradox of organizational change: engineering organizations with behavioral systems analysis.
mylen [45]

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Paradox of Organizational Change: Engineering Organizations with Behavioral Systems Analysis. by. Maria E. Malott.

7 0
1 year ago
A light bar AD is suspended from a cable BE and supports a 20-kg block at C. The ends A and D of the bar are in contact with fri
babymother [125]

Answer:

Tension in cable BE= 196.2 N

Reactions A and D both are  73.575 N

Explanation:

The free body diagram is as attached sketch. At equilibrium, sum of forces along y axis will be 0 hence

T_{BE}-W=0 hence

T_{BE}=W=20*9.81=196.2 N

Therefore, tension in the cable, T_{BE}=196.2 N

Taking moments about point A, with clockwise moments as positive while anticlockwise moments as negative then

196.2\times 0.125- 196.2\times 0.2+ D_x\times 0.2=0

24.525-39.24+0.2D_x=0

D_x=73.575 N

Similarly,

A_x-D_y=0

A_x=73.575 N

Therefore, both reactions at A and D are 73.575 N

7 0
3 years ago
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