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Shalnov [3]
3 years ago
12

A waste treatment pond is 50m long and 25m wide, and has an average depth of 2m.The density of the waste is 75.3 lbm/ft3. Calcul

ate the weight of the pond contents in lbf, using a single dimensional equation for your calculation.
Engineering
1 answer:
weeeeeb [17]3 years ago
6 0

Answer:

The weight of the pond contents is 6,643,233.22 lbf

Explanation:

Weight = density × volume × acceleration due to gravity

density = 75.3lbm/ft^3 = 75.3lbm/ft^3 × 0.45359kg/1lbm × (3.2808ft/1m)^3 = 1206.14kg/m^3

volume = length×width×depth = 50m×25m×2m = 2500m^3

acceleration due to gravity = 9.8m/s^2

Weight = 1206.14×2500×9.8 = 29,550,430N = 29,550,430N × 1lbf/4.4482N = 6,643,233.22lbf

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B. The thickness of the heated region near the plate is increasing.

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From law of conduction, we observe that heat transfer rate will decrease based on a smaller rate of temperature, the thickness therefore increases while the local heat transfer coefficient decreases with distance.

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Answer:

Superficial design improvements are typically only trivial changes to a design, while functional design improvements can change the way a product or process is used to significantly enhance performance.

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<em>Superficial design improvements are typically only trivial changes to a design, while functional design improvements can change the way a product or process is used to significantly enhance performance.</em>

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2 years ago
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