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Dmitriy789 [7]
3 years ago
14

When a bicycle coasts uphill, it moves slower and slower as it climbs. Why?

Physics
2 answers:
astra-53 [7]3 years ago
6 0

Letter B because it is gaining more potential energy as it SLOWLY climbs up the hill.

the less motion the more potential energy there is

Elenna [48]3 years ago
5 0

Answer:

B. Its potential energy is transforming into kinetic energy.

Explanation:

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An object moving at 15 m/s slows uniformly at a rate of 2.0 m/s each second for 5.0 s. What is its final speed?​
NeX [460]
Hey there!

We are given ,

Acceleration, a = -2m/s^2

Initial velocity , u = 15m/s

Time , t = 5 seconds

We know that ,
V=u+at

Now , final speed ,

V = 15+(-2)(5)

V = 15-10

V = 5 m/s -> final speed

Hope this helps you dear :)
Have a good day <3

8 0
2 years ago
A 241 kg mass is lifted 1.8 m. What is the potential energy of the mass (in J)?
Korolek [52]

Answer:

mass is lifted 1.8 m. What is the potential energy of the mass 4. A 100 kg

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lora16 [44]
I think the answer is 60 cm.
5 0
4 years ago
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Fill in the blank with the appropriate numbers for both electrons and bonds(considering that single bonds are counted as one, do
tekilochka [14]

Answer:

1.Fluorine is having 7 number of electrons and 1 makes bond.

     Electronic configuration  -  1S² 2S² 2P⁵  

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2.Oxygen is having 6 balance electron and 2 makes bonds.

    Electronic configuration  -  1S² 2S² 2P⁴  

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3.Nitrogen is having 5 balance electron and 3 makes bonds.

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4. Carbon having 4 balance electron and 4  makes bonds.

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3 0
3 years ago
Which accounts for an increase in the temperature of a gas that is kept a constant volume
oksian1 [2.3K]

Answer:

An increase in pressure

Explanation:

The ideal gas law states that:

pV=nRT

where

p is the gas pressure

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R is the gas constant

T is the temperature of the gas

in the equation, n and R are constant. For a gas kept at constant volume, V is constant as well. Therefore, from the formula we see that if the temperature (T) is increase, the pressure (p) must increase as well.

7 0
3 years ago
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