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Ugo [173]
3 years ago
15

Calculate how much work is done when a force of 1600 N pulls a car through a distance of 40 m in the direction of the force.

Physics
1 answer:
Ulleksa [173]3 years ago
8 0

Answer: work done = 64,000J or 64KJ.

Explanation:

Work is said to be done if a force applied makes the object to move through a distance in the direction of the applied force. Work is the product of force and perpendicular distance in the direction of the applied force. It is represented by W, measured in Joules(J) and a scalar quantity.

Thus, work done(J)= force(N) × distance(m)

From the the question,

applied force= 1600N

distance=40m

Therefore, work= 1600 × 40

W= 64,000J

But, 1 kilojoules = 1000J

Therefore, 64,000J = 64,000 ÷ 1000

= 64KJ

Work done is 64KJ

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Correct Question:-

A jack exerts a vertical force of 4.5 × 10³

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\\  \\

Given :-

\star  \sf  \small force = 4.5 \times  {10}^{3}  \: newton

\star  \sf  \small distance = 0.25 \: meter

\\  \\

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\\  \\

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\\  \\

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\\  \\

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\\  \\

\dashrightarrow \sf work = (4.5 \times 1 {0}^{3} ) \times  \cancel \frac{5}{10}  \\

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\\  \\

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\\  \\

\dashrightarrow \sf work =  \dfrac{45}{10 {}^{0} }  \times 1 {0}^{3 - 1} \times  \dfrac{1}{2} \\

\\  \\

\dashrightarrow \sf work =  \dfrac{45}{10 {}^{0} }  \times 1 {0}^{2} \times  \dfrac{1}{2} \\

\\  \\

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\dashrightarrow \sf work =  \dfrac{45 \times 10 \times  \cancel{10}}{ \cancel2} \\

\\  \\

\dashrightarrow \sf work =  \dfrac{45 \times 10 \times 5}{ 1} \\

\\  \\

\dashrightarrow \sf work =225 \times 10

\\  \\

\dashrightarrow \bf work =\red{2250\: joule}

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