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3 years ago

Calculate how much work is done when a force of 1600 N pulls a car through a distance of 40 m in the direction of the force.

Physics

1 answer:

Ulleksa [173]3 years ago

8 0

Answer: work done = 64,000J or 64KJ.

Explanation:

Work is said to be done if a force applied makes the object to move through a distance in the direction of the applied force. Work is the product of force and perpendicular distance in the direction of the applied force. It is represented by W, measured in Joules(J) and a scalar quantity.

Thus, work done(J)= force(N) × distance(m)

From the the question,

applied force= 1600N

distance=40m

Therefore, work= 1600 × 40

W= 64,000J

But, 1 kilojoules = 1000J

Therefore, 64,000J = 64,000 ÷ 1000

= 64KJ

Work done is 64KJ

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3 years ago

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$\begin{gathered} r=\text{ radius} \\ v=\text{ velocity} \\ q=\text{ charge} \\ B=\text{ magnetic field} \end{gathered}$

We can determine the quotient between the velocity and the charge of the deuteron particle from the formula. First, we divide both sides by the mass:

$\frac{r_d}{m_d}=\frac{v}{q_B_}$

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$\frac{Br_d}{m_d}=\frac{v}{q}$

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$r_p=\frac{m_p}{B}(\frac{Br_d}{m_d})$

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1 year ago

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3 years ago

Read 2 more answers

A 1kg cannon ball.is fired horizontally with an initial velocity of 5m/s. If the cannon was atop a wall 20m above the ground, wh

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Answer:

Ek = 196.2 [J]

Explanation:

The question concerns the KE kinetic energy.

That is, we must find the kinetic energy at the moment the cannon is fired and the kinetic energy of when the ball hits the ground after having fallen 20 meters.

At the moment when the ball is fired it is 20 meters above ground level. If the ground level is taken as the reference level of potential energy, where it is equal to zero, in this way when the ball is at the highest (20 meters) you have the maximum potential energy.

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The kinetic energy in the initial state can be easily calculated by means of the following equation.

$E_{k1}=\frac{1}{2} *m*v^{2}\\E_{k1}=0.5*1*(5)^{2}\\E_{k1}=12.5 [J]$

Therefore the change in KE

$E_{k} = 208.7 - 12.5\\E_{k} = 196.2 [J]$

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3 years ago

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2, 3 and 5.

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