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Vinil7 [7]
3 years ago
14

The propeller of an airplane is at rest when the pilot starts the engine; and its angular acceleration is a constant value. Two

seconds later, the propeller is rotating at 10rad/s. Through how many revolutions has the propeller rotated through during the first two seconds?
Physics
2 answers:
UkoKoshka [18]3 years ago
5 0

Answer: The propeller has rotated 5 revolutions

Explanation:

Number of revolutions = angular velocity/ time

Given:

Angular velocity=10rad/s

Time=2seconds

Number of revolutions = 10/2= 5 revolutions.

Maurinko [17]3 years ago
3 0

Answer:0.318 revolutions

Explanation:

Given

Initially Propeller is at rest i.e. \omega _0=0 rad/s

after t=10 s

\omega =10 rad/s

using \omega =\omega _0+\alpha t

10=0+\alpha \cdot 10

\alpha =1 rad/s^2

Revolutions turned in 2 s

\theta =\omega _0t+\frac{\alpha t^2}{2}

\theta =0+\frac{1\times 2^2}{2}

\theta =2 rad

To get revolution \frac{\theta }{2\pi }

=\frac{2}{2\pi}=0.318\ revolutions

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