Answer:
22.44°C will be the final temperature of the water.
Explanation:
Heat lost by tin will be equal to heat gained by the water

Mass of tin = 
Specific heat capacity of tin = 
Initial temperature of the tin = 
Final temperature =
=T

Mass of water= 
Specific heat capacity of water= 
Initial temperature of the water = 
Final temperature of water =
=T



On substituting all values:

we get, T = 22.44°C
22.44°C will be the final temperature of the water.
It would be 12.4 moles of HCL because you multiply 6.2 by how many moles of HCL in te equation then divide it by how many moles of h2 in the equation so you multiple 6.2 by 2 moles because there’s two moles of HCL which gives you 12.4 then you divide it by one because in the equation there is only 1 mole of H2
Answer: The temperature of 0.6 moles of fluorine that occupy 15 L at 2,300 mmHg is 920 K
Explanation:
According to ideal gas equation:

P = pressure of gas = 2300 mm Hg = 3.02 atm (760mmHg=1atm)
V = Volume of gas = 15 L
n = number of moles = 0.6
R = gas constant =
T =temperature = ?


Thus the temperature of 0.6 moles of fluorine that occupy 15 L at 2,300 mmHg is 920 K