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Elanso [62]
3 years ago
9

A car speeds up and accelerates for 5.1 seconds at a rate of 2.2 m/s2. if the car's initial velocity was 9.3 m/s, what was the c

ar's final velocity
after accelerating?
-9.7m/s
-11.2m/s
1.9m/s
20.5m/s
Physics
1 answer:
sp2606 [1]3 years ago
6 0

Recall the definition of average acceleration:

<em>a</em> = (<em>v</em> - <em>u</em>)/∆<em>t</em>

where <em>u</em> and <em>v</em> are the initial and final velocities, respectively.

So we have

2.2 m/s² = (<em>v</em> - 9.3 m/s) / (5.1 s)

<em>v</em> - 9.3 m/s = (2.2 m/s²) * (5.1 s)

<em>v</em> = 9.3 m/s + (2.2 m/s²) * (5.1 s)

<em>v</em> = 20.52 m/s ≈ 21 m/s

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Explanation:

Given that,

Two resistors of resistance 6 ohm and 3 ohm are connected in series and then in parallel.

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R_{eq}=R_1+R_2

For parallel combination,

\dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}

When 6 ohm and 3 ohm are in series,

R_s=6+3\\\\R_s=9\ \Omega

When 6 ohm and 3 ohm are in paralle,

\dfrac{1}{R_p}=\dfrac{1}{6}+\dfrac{1}{3}\\\\R_p=2\ \Omega

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4.689 years

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Given :

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