Answer:
6.13428 rev/s
Explanation:
= Final moment of inertia = 4.2 kgm²
I = Moment of inertia with fists close to chest = 5.7 kgm²
= Initial angular speed = 3 rev/s
= Final angular speed
r = Radius = 76 cm
m = Mass = 2.5 kg
Moment of inertia of the skater is given by
In this system the angular momentum is conserved
The rotational speed will be 6.13428 rev/s
Answer:
The velocity of the particle from T = 0 s to T = 4 s is;
0.5 m/s
Explanation:
The given parameters from the graph are;
The initial displacement (covered) at time, t₁ = 0 s is x₁ = 1 m
The displacement covered at time, t₂ = 4 s is x₂ = 3 m
The graph of distance to time, from time t = 0 to time t = 4 is a straight line graph, with the velocity given by the rate of change of the displacement to the time which is dx/dt which is also the slope of the graph given as follows;
The velocity of the particle from t = 0 s to t = 4 s = 1/2 m/s = 0.5 m/s.