Answer:
V1 = 1.721 * V2
Explanation:
To start with, we assume that both lift forces are equal, such that
L2 = L1
1 is that of the level at 10000 m, and 2 is that of the level at sea level.
Next, we try and substitute the general formula for both forces such that
C(l).ρ1/2.V1².A = C(l).ρ2/2.V2².A
On further simplification, we have
ρ1.V1² = ρ2.V2², making V1 subject of formula, we have
V1 = √(ρ2/ρ1). V2²
Using the values of density for air at 10000 m and at sea level(source is US standard atmosphere), we have
V1 = √(1.225/0.4135) * V2
V1 = √2.9625 * V2
V1 = 1.721 * V2
Answer:
The program is as follows:
i = 1
while(i<11):
j = 1
while(j<=i):
print('*', end = '')
j += 1
i += 1
print()
Explanation:
Initialize i to 1
i = 1
The outer loop is repeated as long as i is less than 11
while(i<11):
Initialize j to 1
j = 1
The inner loop is repeated as long as j is less than or equal i
while(j<=i):
This prints a *
print('*', end = '')
This increments j and ends the inner loop
j += 1
This increments i
i += 1
This prints a blank and ends the inner loop
print()
Answer:
See explaination
Explanation:
We can describe Aspiration Effect as a phenomenon of providing an allowance for the release of air from the mold cavity during the metal pouring.
See the attached file for detailed solution of the given problem.
No I don’t sorry, I hope you do well
Answer:
QPSK: 7.5 MHz
64-QAM:2.5 MHz
64-Walsh-Hadamard: 160 MHz
Explanation:
See attached picture.