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maria [59]
4 years ago
14

What is the angle of reflection

Physics
2 answers:
Naddika [18.5K]4 years ago
7 0
The angle of reflection of light is equal to 90 degrees
Pachacha [2.7K]4 years ago
7 0

The answer of edge is 45 degrees.

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an athlete runs 300 m up a hill at a steady speed of 3.0 m/s. She then immediately runs the same distance at 6.0 m/s . What is h
mina [271]

Answer:

4.0 m/s

Explanation:

In the first part of the run, the athlete runs a distance of

d_1 = 300 m

at a speed of

v_1 = 3.0 m/s

So, the time he/she takes is

t_1 = \frac{d_1}{v_1}=\frac{300}{3.0}=100 s

In the second part of the run, the athlete covers an additional distance of

d_2 = 300 m

with a speed

v_2 = 6.0 m/s

So, the time taken in this second part is

t_2 = \frac{d_2}{v_2}=\frac{300}{6.0}=50 s

So, the total distance covered is

d = 300 m + 300 m = 600 m

And the total time taken

t = 100 s + 50 s = 150 s

Therefore, the average speed for the entire trip is

v=\frac{d}{t}=\frac{600}{150}=4.0 m/s

4 0
4 years ago
Yo someone help me on dis jawnt rq plzzz!
Phantasy [73]

Answer:

the answer is 45.6 kg = 45600 g

7 0
3 years ago
What are tadpoles? How does it look like
AnnZ [28]

Answer: a tadpole is the first or second step into the evolution for a frog

Explanation: a frog starts with the egg then it becomes a tadpole for 6 to 12 weeks before it can start going out the water.

6 0
3 years ago
Read 2 more answers
A book of mass 3 kg rests on a plank. You tilt one end of the plank and slowly increase the angle of the tilt. The coefficient o
bonufazy [111]

Answer: 24.7 degrees Max

Explanation:

m*g = 3 * 9.8 = 29.4 N. = Wt. of book.



Fp = 29.4*sin A = Force parallel to the
plank.



Fn = 29.4*Cos A = Force perpendicular to
the plank.



Fs = u*Fn = 0.46*29.4*Cos A

Fp-Fs = m*a


29.4*sin A - 0.46*29.4*Cos A = m*0 = 0


29.4*Sin A = 0.46*29.4*Cos A


Sin A = 0.46*Cos A


Divide both sides by Cos A:


Sin A/Cos A = 0.46


Replace Sin A/Cos A with Tan A:


Tan A = 0.46


A = 24.7 degrees Max.

8 0
3 years ago
A uniform cylindrical steel wire (density: 7.8 x 103 kg/m3), 58.0 cm long and 1.34 mm in diameter, is fixed at both ends. To wha
lbvjy [14]

Answer:

T= 354.65 N

Explanation:

Given that

ρ= 7800 kg/m³

L= 58 cm

d=1.34 mm

f= 311 Hz

T= Tension

Speed of wave ,V

V = f λ      

V = f L

V= 311 x 0.58 m/s

V=180.38 m/s

Area of cross sectional

A= πr² mm²

A= 3.14 x 0.67² mm²

A=1.41 mm²

Mass = Density x Volume

m=7800\times 1.41\times 10^{-6}\ kg/m

m=0.0109 kg/m

Tension ,T

T=m V^2

T= 0.0109 x 180.38² N

T= 354.65 N

     

3 0
3 years ago
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