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erastova [34]
3 years ago
12

Plz Help me This is all my homework The one is orange is the ones i need help in

Physics
2 answers:
IrinaVladis [17]3 years ago
8 0

Convection is the transfer of heat through a fluid

Conduction is the heat or electric current from one substance to another

Radiation is energy that radiated or transmitted

Ex: Convection- A pot of water is being boiled- the heat is being transferred to to the water

Ex2: Conduction- I have a plate filled with hot food- the heat from the food is being transferred to the plate, making the plate hot as well.

Ex3: Radiation- There is a dog by the fire place, the dog is being warmed- the heat from the fire is being transferred over to the dog

Hope this will help you with your homework :)

dangina [55]3 years ago
6 0
14. Radiation
17. Radiation
18. Convection
21. Conduction
22. Radiation
23. Convection
24. Conduction
25. Conduction
26. Radiation
27. Conduction
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A father is trying to teach his child to ice skate. As the child stands still, the father pushes him forward with an acceleratio
rjkz [21]

Hi there!

We can use Newton's Second Law:

\Sigma F = ma

∑F = net force (N)

m = mass (kg)

a = acceleration (m/s²)

We are given the mass and acceleration, so:

∑F = 20 · 2 = <u>40 N</u>

4 0
2 years ago
"Which of the following statements about electrons is not true?
gogolik [260]

Answer:

B) Within an atom, an electron can have only particular energies.

Explanation:

As we know that electrons have energy but apart from electrons we know that protons and neutrons inside the nucleus of atom will also have energy in them.

rest all the statements are true as we have

A) Electrons orbit the nucleus rather like planets orbiting the Sun.

TRUE, because electrons can move in stationary orbit around the nucleus

C) Electrons can jump between energy levels in an atom only if they receive or give up an amount of energy equal to the difference in energy between the energy levels.

Difference amount of energy is lost or absorbed by the electron in form of photons

D) An electron has a negative electrical charge.

Charge of an electron is given as -1.6 \times 10^{-19} C

E) Electrons have very little mass compared to protons or neutrons

Mass of an electron is given as

m_e = 9.11 \times 10^{-31} kg

mass of proton or neutron

m_p = 1.67 \times 10^{-27} kg

7 0
3 years ago
How to calculate the slope of position time graph?
Mashcka [7]

Answer:

The slope of a position-time graph can be calculated as:

m=\frac{\Delta y}{\Delta x}

where

\Delta y is the increment in the y-variable

\Delta x is the increment in the x-variable

We can verify that the slope of this graph is actually equal to the velocity. In fact:

\Delta y corresponds to the change in position, so it is the displacement, \Delta s

\Delta x corresponds to the change in time \Delta t, so the time interval

Therefore the slope of the graph is equal to

m=\frac{\Delta s}{\Delta t}

which corresponds to the definition of velocity.

3 0
3 years ago
Which of the following best describes why tidal energy is considerd a renewable resorce?
Gemiola [76]

Answer:

It is green. Aside from being renewable, tidal energy is also an environmentally friendly energy source because it does not take up a lot of space and does not emit any greenhouse gases.

Explanation:

5 0
2 years ago
When beryllium-7 ions (m = 11.65 × 10-27 kg) pass through a mass spectrometer, a uniform magnetic field of 0.205 T curves their
AysviL [449]

Answer:

ratio =0.3075 T

Explanation:

The magnetic field B creates a force on a moving charge such that

F = qvB

Now this causes a centripetal acceleration

F =  = mv^2/r

 so

qvB = mv^2/r ...........(i)

B = mv/(rq)  ...............(ii)

If  accelerating potential V is  same and  then  kinetic energy equals the potential energy difference

\frac{1}{2} mv^2 = Vq

v = \sqrt{(2Vq/m)}      put these value in equation (ii)

B = m\frac{\sqrt{(2Vq/m)} }{rq}  

simplifying we get  

B =m \frac{(\sqrt{ 2Vm/q})}{r}

for same location r will be same in both case

B_{7} = \frac{ \sqrt{(m_{7})(2V/q) }}{r}      ..............(iii)

B_{10} = \frac{ \sqrt{(m_{10})(2V/q) }}{r}    ..........(iv)

 dividing (iv) and (iii) equation we get

\frac{B_{10}}{B_{7}}   =   \sqrt{\frac{m_{10}}{{m_7}} }

{B_{10}}  =  B_{7}  \sqrt{\frac{m_{10}}{{m_7}} }

B_{10}       = 0.2574T\sqrt{\frac{  (1.663x10^-26}{(1.165x10^-26)}

so on solving we get  

             =0.3075 T

5 0
3 years ago
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