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Scrat [10]
3 years ago
13

Two children stretch a jump rope between them and send wave pulses back and forth on it. The rope is 4.5 m long, its mass is 0.4

2 kg, and the force exerted on it by the children is 71 N. (a) What is the linear mass density of the rope (in kg/m)?
(b) What is the speed of the waves on the rope (in m/s)?
Physics
1 answer:
lions [1.4K]3 years ago
7 0

Answer:

density = 0.0933 kg/m

speed = 27.581 m/s

Explanation:

given data

length L = 4.5 m

mass m = 0.42 kg

force  F = 71 N

to find out

mass density and speed

solution

we find linear mass density

linear mass density  = mass / length

put here all value

density = 0.42 / 4.5

density = 0.0933 kg/m

and

speed of wave

speed = √(F/density)

speed = √(0.42/0.933)

speed = 27.581 m/s

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A 35.4 kg girl is riding on the back of a 15.23 kg cart. the cart and the kid are both moving eastward at 4.25 m/s when she step
Grace [21]

Answer:

The final  velocity of the cart is  v_c = 7.02 \  m/s

Explanation:

From the question we are told that

    The mass of the girl is  m_g  = 35.4 \ kg

     The mass of the cart is  m_c  = 15.23 \ kg

      The speed of the cart and  kid(girl) is  v = 4.25 \ m/s

     The final velocity of  the girl is v_g  = 3.06 \  m/s

Let assume that velocity eastward is  positive and velocity westward is negative (Note that if we assume vise versa it wouldn't affect the answer )

   The total momentum of the system before she steps off the back of the cart

is mathematically evaluated as

        p__{T1}} = (m_g + m_c) * v

substituting values

        p__{T1}} = (35.4 + 15.23) * 4.25

        p__{T1}} =215.17 \  kg m /s

The total momentum after she steps off the back of the cart is mathematically evaluated as

        p__{T2}} = (m_g * v_g ) +(  m_c * v_c )

Where  v_c  is the final velocity of the cart

substituting values    

      p__{T2}} = (35.4 * 3.06 ) +(  15.23 * v_c )

       p__{T2}} = 108. 324 + 15.23  v_c

Now according to the law of conservation of momentum

       p__{T1}} =p__{T2}}

So  

       215.17 \  kg m /s =  108. 324 + 15.23  v_c

=>      v_c = 7.02 \  m/s

Since the value is positive it implies that the cart moved eastward

7 0
3 years ago
the radius of earth is 6370km and of mars is 3400km. if an object weighs 200N or earth , what will be it's weight on mars. the m
4vir4ik [10]
The weight of the object on mars is about 80n
4 0
3 years ago
An object with a mass of 2.0 kg accelerates 2.0 m/s2 when an unknown force is applied to it. What is the amount of the force?
MAXImum [283]

force is mass * acceleration  

so 2kg * 2m/s^2 = 4 N

5 0
3 years ago
A horizontal insulating rod of length 11.8-cm and charge 19 nC is in a plane with a long straight vertical uniform line charge.
SCORPION-xisa [38]

Answer:

11.962337 × 10^-4 N

Explanation:

Given the following :

Length L = 11.8

Charge = 29nC = 29 × 10^-9 C

Linear charge density λ = 1.4 × 10^-7 C/m

Radius (r) = 2cm = 2/100 = 0.02 m

Using the relation:

E = 2kλ/r ; F =qE

F = 2kλq/L × ∫dr/r

F = 2*k*q*λ/L × (In(0.02 + L) - In(0.02))

2*k*q*λ/L = [2 × (9 * 10^9) * (29 * 10^9) * (1.4 * 10^-7)]/ 0.118] = 6193.2203 × 10^(9 - 9 - 7) = 6193.2203 × 10^-7 = 6.1932203 × 10^-4

In(0.02 + 0.118) - In(0.02) = In(0.138) - In(0.02) = 1.9315214

Hence,

(6.1932203 × 10^-4) × 1.9315214 = 11.962337 × 10^-4 N

3 0
3 years ago
Comic-book superheroes are sometimes able to punch holes through steel walls. (a) If the ultimate shear strength of steel is tak
Katena32 [7]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

shear stress is the measure of the material's resistance to cause "sliding" motion of its layers. 
<span>Since the hero has to take a cylindrical piece of metal out, the area which will cause this force is 2*pi*r*l (put r and l in SI units to get answer in Newtons) </span>
<span>so the force required is shear strength into this area (2.60109 * 2 * pi * r * l) </span>
7 0
3 years ago
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