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Naya [18.7K]
4 years ago
11

Fomula of displacementtthelp

Physics
2 answers:
matrenka [14]4 years ago
5 0
Formula for Displacement: D = ΔX = (Xf - Xi)
Usimov [2.4K]4 years ago
4 0

Introduction to the Displacement and Acceleration Equation. This equation relates displacement, original velocity, constant acceleration, and time: It reads: Displacement equals the original velocity multiplied by time plus one half the acceleration multiplied by the square of time.

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Deneb and the Sun are two stars. Deneb has a diameter that is 109-200 times greater than that of the sun. When seen from earth,
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I believe it is 
B)The Sun is closer than Deneb


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3 years ago
A charged box (m=445 g, ????=+2.50 μC) is placed on a frictionless incline plane. Another charged box (????=+75.0 μC) is fixed i
victus00 [196]

The concept required to perform this exercise is given by the coulomb law.

The force expressed according to this law is given by

F= \frac{kqQ}{r^2}

Where,

k = 8.99 * 10^9 N m^2 / C^2.

q = charges of the objects

r= distance/radius

Our values are previously given, so

q= 2.5*10^{-6}C\\Q= 75*10^{-6}C\\r=0.59

Replacing,

F=\frac{kqQ}{r^2}

F= \frac{(8.99 x 10^9)(2.5*10^{-6})(75*10^{-6})}{0.59^2}

F= 4.8423N

The force acting on the block are given by,

F-mgsin\theta = ma

a = \frac{F-mgsin\theta}{m}

a = \frac{4.8423-(0.445)(9.8)sin(35)}{0.445}a = 10.31m/s^2

Therefore the box is accelerated upward.

3 0
3 years ago
which of these waves requires a medium to travel through light wave electromagnetic waves sound wave microwave
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Sound waves require a medium to travel through. :D 
7 0
4 years ago
Read 2 more answers
A car accelerates uniformly in a straight line
Alinara [238K]

Recall that

{v_f}^2={v_i}^2=2a\Delta x

The car starts from rest, so v_i=0, and we get

{v_f}^2=2\left(2.8\dfrac{\rm m}{\mathrm s^2}\right)(69\,\mathrm m)\implies v_f\approx19.66\dfrac{\rm m}{\rm s}

4 0
3 years ago
HELP!!
QveST [7]

Answer:

Total displacement 155 m

Explanation:

From the question, the formula to apply will be that of cosine rule where:

c=\sqrt{a^2+b^2-2ab*cosC}

where

a= 43 m , b=130m and c =? , <C=28° + 90° =118°

Substituting values in the equation as;

c=\sqrt{43^2+130^2-2*43*130*cos118}

c=\sqrt{1849+16900-11180*-0.46947} \\\\c=\sqrt{1849+16900+5249} \\\\c=\sqrt{23998} \\\\\\c=155m

6 0
3 years ago
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