Fomula of displacementtthelp
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GPE = mgh Where m is the mass of the object (kg), g is acceleration due to gravity (which I will assume to be 9.81ms-2), and h is the height of the object above ground level. This is used in cases where the object is close to the earth, since any change in gravitational force is negligible.
Substituting in the numbers:
Substituting in the numbers:
Consider the upward direction of motion as positive and downward direction of motion as negative.
a = acceleration due to gravity in downward direction = - 9.81
v₀ = initial velocity of runner in upward direction = 2.0
v = final velocity of runner at the highest point = 0
x = distance by which center of mass of runner rise = ?
Using the kinematics
v² = v²₀ + 2 a x
inserting the values
0² = 2² + 2 (- 9.81) x
x = 0.204 m