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Bogdan [553]
3 years ago
13

Some of the enzymes that oxidize sugars to yield useable cellular energy (for example, ATP) are regulated by phosphorylation. Fo

r these enzymes, would you expect the inactive form to be the phosphorylated form or the dephosphorylated form? Explain your answer.
Chemistry
1 answer:
Elena-2011 [213]3 years ago
3 0

Explanation:

The enzyme undergoes reaction and produces cellular energy is likely to be inactive when the enzyme is phosphorylated and active when the enzyme is dephosphorylated.

The reason for the above statement is that when there is a need for the ATP to the body, the enzyme must be active to produce the energy currency. Also, ATP in the body is the source of phosphate which it transfer to the proteins or other biological molecules.

In a case where ATP is plentiful in the body, the enzyme must be inactive or turned off via the transfer of the phosphate group. Thus, phosphorylated enzyme is inactive form.

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6. If 4 mole of the rocket fuel ammonium perchlorate, NH4C/04 (s) is
Bond [772]

Answer:

144g of H₂O

Explanation:

3NH₄ClO₄(s) + 3Al → Al₂O₃(s) + AlCl₃(s) + 3NO(g) + 6H₂O(g)

From the equation:

3 moles of NH₄ClO₄ produced 6 moles of H₂O

4 moles of NH₄ClO₄ produced ? moles of H₂O

(4 ₓ 6)/3 = \frac{24}{3} = 8 moles of H₂O

1 mole of H₂O = (1 × 2) + 16 = 18g (The Relative Molecular mass of H₂O)

8 moles of H₂O = ?

Therefore 8 × 18 = 144g

=144g of H₂O

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3 years ago
Which reaction is most likely to have a positive ΔSsys?
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3 years ago
Use the drop-down menus to complete the statement.
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Answer:commutator then current are the answers. I just took the question.

Explanation:

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3 years ago
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Which of these statements best describes how an increase in the amount of Sun’s heat reflected by the Earth’s surface and atmosp
Korolek [52]

If the Suns heat is being reflected, then it is making the Earth cooler.

7 0
3 years ago
At a certain temperature, the vapor pressure of pure benzene ‍ is atm. A solution was prepared by dissolving g of a nondissociat
erastova [34]

Answer:

Molar mass of solute: 300g/mol

Explanation:

<em>Vapor pressure of pure benzene: 0.930 atm</em>

<em>Assuming you dissolve 10.0 g of the non-volatile solute in 78.11g of benzene and vapour pressure of solution was found to be 0.900atm</em>

<em />

It is possible to answer this question based on Raoult's law that states vapor pressure of an ideal solution is equal to mole fraction of the solvent multiplied to pressure of pure solvent:

P_{sln} = X_{solvent}P_{solvent}^0

Moles in 78.11g of benzene are:

78.11g benzene × (1mol / 78.11g) = <em>1 mol benzene</em>

Now, mole fraction replacing in Raoult's law is:

0.900atm / 0.930atm = <em>0.9677 = moles solvent / total moles</em>.

As mole of solvent is 1:

0.9677× total moles = 1 mole benzene.

Total moles:

1.033 total moles. Moles of solute are:

1.033 moles - 1.000 moles = <em>0.0333 moles</em>.

As molar mass is the mass of a substance in 1 mole. Molar mass of the solute is:

10.0g / 0.033moles = <em>300g/mol</em>

8 0
3 years ago
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