Answer:
The unknown temperature is 304.7K
Explanation:
V1 = 100mL = 100*10^-3L
P1 = 99.10kPa = 99.10*10³Pa
V2 = 74.2mL = 74.2*10^-3L
P2 = 133.7kPa = 133.7*10³Pa
T2 = 305K
T1 = ?
From combined gas equation,
(P1 * V1) / T1 = (P2 * V2) / T2
Solving for T1,
T1 = (P1 * V1 * T2) / (P2 * V2)
T1 = (99.10*10³ * 100*10^-3 * 305) / (133.7*10³ * 74.2*10^-3)
T1 = 3022550 / 9920.54
T1 = 304.67K
T1 = 304.7K
Hey There!!~
Your best answer choice is 10280 or 10,280.
Because, 1 x 1025 = 1025 + 3 = 1028 x 10 = 10280 or 10,280.
Hope This Helps....!!
Answer:
oxygen is an example of a diatomic molecule found in earth's atmosphere!
Explanation:
Answer:
Explanation:1.8
×
10
24
water molecules.
Explanation:
There are
6.022
×
10
23
molecules in a mole.
There are
18.01528
grams of water per mole of water.
These can be figured out using the concept of moles and molecular weight. I have attached a video that provides a good explanation.
Explanation of moles and molecular weight
Now you have all the information needed to solve the problem.
You start out with 54 grams of water. You want to convert that into molecules, but how can you do that? You can't go directly from grams to molecules because there is no easy unit conversion. However, you can go from grams to moles using
18.01528
grams of water per mole of water.
From there, you can go from moles to molecules using
6.022
×
10
23
molecules in a mole.
A T chart is useful for this kind of problem.
54 g H
2
O
×
1 mol H
2
O
18.0152 g H
2
O
×
6.022
×
10
23
molecules
1 mol H
2
O
54
g H
2
O
×
1 mol H
2
O
18.0152
g H
2
O
×
6.022
×
10
23
molecules
1 mol H
2
O
Notice when you apply this T chart, the units cancel out, leaving molecules in the final answer, which is the correct units.
Now actually multiply everything out
54
×
6.022
×
10
23
18.0152
=
1.805
×
10
24
You are left with
1.8
×
10
24
water molecules (rounded to two sig figs).
Answer:
B.
Explanation:
ive done this before trust
