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ELEN [110]
3 years ago
12

How do you do number 2 becUse i honestly don't get it

Chemistry
1 answer:
grandymaker [24]3 years ago
8 0
53.5 g MgCl2 /95.21 g/mol = 0.5619 Moles MgCl2. Since the ratio is 3MgCl : 2Na3PO4 you multiply 0.5619 x 2/3 (since you're solving for NaPO, the 2 goes on top) which shows we have .3746 Moles of NaPO. Multiply times it's molar mass so 0.3746x 163.94g/mol= 61.4136 grams NaPO. I believe.
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____________ are solutions that resist changes in ph when moderate amounts of acids or bases are added and contain ions or molec
Kaylis [27]
<u><em>Buffers</em></u> <span>are solutions that resist changes in ph when moderate amounts of acids or bases are added and contain ions or molecules that react with oh- or h when these ions are introduced into solution.</span>
5 0
3 years ago
Balance the chemichal equation:<br> NH3+CuO➡️Cu+N2+H2O
Gala2k [10]
2NH3+3CuO➡️3Cu+N2+3H2O
4 0
3 years ago
What steps would you take in a lab to prepare 1000 mL of a 2 M NaCl solution
amm1812

Answer:

The answer to your question is below

Explanation:

Data

Volume = 1000 ml

Concentration = 2M

molecule = NaCl

Process

1.- Calculate the number of moles of NaCl

Molarity = moles/Volume

-Solve for volume

moles = Molarity x Volume (liters)

-Substitution

moles = 2 x 1

-Result

moles = 2

2.- Determine the molar mass of NaCl

NaCl = 23 + 35.5 = 58.5 g

3.- Calculate the mass of NaCl to prepare the solution

               58.5 g -----------------  1mol

                   x      -----------------  2 moles

                       x = (2 x 58.5) / 1

                       x = 117g

4.- Weight 117 g of NaCl, place them in a volumetric flask (1 l), and add enough water to prepare the solution.

7 0
4 years ago
I WILL GIVE 50 POINTS AND BRAINLIEST What is the volume of 41.2g argon at stp???
iragen [17]

Answer:

1645.86

Explanation:

4 0
3 years ago
Calculate the number of C, H, and O atoms in 1.75 g of squaric acid
strojnjashka [21]
As far as I remember, the needed formula for squaric acid is C4H2O4.
According to this one mole should be  114.06 g., which means we have <span>0.015mol of this acid.
Then we can  easly calculate : </span><span>4(0.015) = 0.06 mol for both for Carbon and Oxygen and </span><span>0.03 mol of Hydrogen.
</span><span>To get more clear answer, we multiply by avogadros : 
</span><span>6.022 x 10^23. Hope everything is clear! regards</span>
4 0
3 years ago
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