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3 years ago

What is the law of conservation of energy?

1 answer:

6 0

The law of conservation of energy, a fundamental concept of physics, states that the total amount of energy remains constant in an isolated system. It implies that energy can neither be created nor destroyed, but can be change from one form to another.

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A 1300 kg steel beam is supported by two ropes. (Figure

Dmitriy789 [7]

Relative to the positive horizontal axis, rope 1 makes an angle of 90 + 20 = 110 degrees, while rope 2 makes an angle of 90 - 30 = 60 degrees.

By Newton's second law,

the net horizontal force acting on the beam is

$R_1 \cos(110^\circ) + R_2 \cos(60^\circ) = 0$

where $R_1,R_2$ are the magnitudes of the tensions in ropes 1 and 2, respectively;

the net vertical force acting on the beam is

$R_1 \sin(110^\circ) + R_2 \sin(60^\circ) - mg = 0$

where $m=1300\,\rm kg$ and $g=9.8\frac{\rm m}{\mathrm s^2}$ .

Eliminating $R_2$ , we have

$\sin(60^\circ) \bigg(R_1 \cos(110^\circ) + R_2 \cos(60^\circ)\bigg) - \cos(60^\circ) \bigg(R_1 \sin(110^\circ) + R_2 \sin(60^\circ)\bigg) = 0\sin(60^\circ) - mg\cos(60^\circ)$

$R_1 \bigg(\sin(60^\circ) \cos(110^\circ) - \cos(60^\circ) \sin(110^\circ)\bigg) = -\dfrac{mg}2$

$R_1 \sin(60^\circ - 110^\circ) = -\dfrac{mg}2$

$-R_1 \sin(50^\circ) = -\dfrac{mg}2$

$R_1 = \dfrac{mg}{2\sin(50^\circ)} \approx \boxed{8300\,\rm N}$

Solve for $R_2$ .

$\dfrac{mg\cos(110^\circ)}{2\sin(50^\circ)} + R_2 \cos(60^\circ) = 0$

$\dfrac{R_2}2 = -mg\cot(110^\circ)$

$R_2 = -2mg\cot(110^\circ) \approx \boxed{9300\,\rm N}$

8 0

2 years ago

A space station, in the form of a wheel 119 m in diameter, rotates to provide an "artificial gravity" of 2.20 m/s2 for persons w

Rina8888 [55]

Well, since it's in the shape of a wheel and the person walks around the edge of it, they must have a centripetal acceleration. Since a=v^2/r you can solve for "v" using 2.20 as your "a" and 59.5 as your "r" (r=half of the diameter).
 a=v^2/r
v=(a*r)^(1/2)=((2.20)*(59.5))^(1/2)= 11.44 m/s.
 After you get "v," plugged that into T=2 pi r/ v. This will give you the 1rev per sec.
 T=2 pi r/ v= T=(2)*(pi)*(59.5)/(11.44)= 32.68 rev/s
 Use dimensional analysis to get rev per min (1rev / # sec) times (60 sec/min).
(32.68 rev/s)(60 s/min)= 1960.74 rev/min

5 0

4 years ago

What could result from regular participation in sports and exercise

shusha [124]

Common health issues that can be positively affected, prevented or controlled by exercise.

5 0

3 years ago

The mass of a giraffe on the moon would be

larisa [96]

Mass is an independent quantity. It can neither be created nor be destroyed. So mass of giraffe will not change on moon.

4 0

3 years ago

Read 2 more answers

Provide the following information for each of the three types of radiations from naturally radioactive materials. Be sure to inc

scoundrel [369]

Alpha radiation: Particles. Each alpha particle is a little bundle of 2 protons and 2 neutrons ... identical to the nucleus of a Helium atom.

Charge . . . +2 elementary charges

Mass . . . 4 Atomic Mass Units

Relative penetrating power . . . low

The effect an electric field would have on it . . . Since the alpha particle has a positive charge, it's repelled by other positive charges, and attracted toward negative charges.

Beta radiation: Particles. Each beta particle is an electron.

Charge . . . -1 elementary charge

Mass . . . 0.00055 AMU

Relative penetrating power . . . medium

The effect an electric field would have on it . . . repelled by other negative charges, and attracted toward positive charges.

Gamma radiation: electromagnetic wave, verrrrry short wave, high frequency

Charge . . . electromagnetic wave, no charge

Mass . . . electromagnetic wave, no mass

Relative penetrating power . . . high

The effect an electric field would have on it . . . electromagnetic wave, no effect

5 0

3 years ago