Answer:
The found acceleration in terms of h and t is:

Explanation:
(The complete question is given in the attached picture. We need to find the acceleration in terms of h and t in this question)
We are given 3 stages of movement of elevator. We'll first model them each of the stage one by one to find the height covered in each stage. After that we'll find the total height covered by adding heights covered in each stage, and equate it to Total height h. From that we can find the formula for acceleration.
<h3>
</h3><h3>
Stage 1</h3>
Constant acceleration, starts from rest.
Distance = 
Velocity = 
<h3>Stage 2</h3>
Constant velocity where
Velocity = 
Distance =
<h3>

</h3><h3 /><h3>Stage 3</h3>
Constant deceleration where
Velocity = 
Distance =

<h3>Total Height</h3>
Total height = y₁ + y₂ + y₃
Total height = 
<h3 /><h3>Acceleration</h3>
Find acceleration by rearranging the found equation of total height.
Total Height = h
h = 5a(t₁)²

Answer:
umm this is not a question
Explanation:
The answer would be to research the need. This should have been done before the project began.
Im not really sure about this im stuck to
What does a physical map show?
the names of countries, states, and cities
the history of an area
the geographical features of an area
the rest stops and restaurants in an area