There are two parts to a wave, the

1 answer:

8 0

Start with the process of elimination. Obviously, color is not a specific component to a wave, so we can cancel that out. While there are frequencies and measurable speeds of waves, those are not considered parts of the wave; nor is the wavelength or the base considered to be a part of the wave. The crest is the highest point of the wave, and is considered a part of the wave, as well as the trough, which is the the lowest point on the wave.

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Consider the following reaction NHAHS(s)NH3(g) + H2S(g) If a flask maintained at 302 K contains 0.196 moles of NH4HS(s) in equil

quester [9]

Answer:

Kc = 3.72 × 10⁶

Explanation:

Let's consider the following reaction:

NH₄HS(g) ⇄ NH₃(g) + H₂S(g)

At equilibrium, we have the following concentrations:

[NH₄HS] = 0.196 M (assuming a 1 L flask)

[NH₃] = 9.56 × 10² M

[H₂S] = 7.62 × 10² M

We can replace this data in the Kc expression.

$Kc=\frac{[NH_{3}] \times [H_{2}S] }{[NH_{4}HS]} =\frac{9.56 \times 10^{2} \times 7.62 \times 10^{2}}{0.196} =3.72 \times 10^{6}$

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2 years ago

In stoichiometric calculations, which quantity MUST be used to convert from one chemical substance to another?

Cloud [144]

The answer is

C) mole ratio

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1 year ago

Crossing a Dd parent with another Dd parent results in

MrRissso [65]

C).dd offspring have a nice day

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2 years ago

In an electroplating apparatus, where does the reduction reaction occur?

Ludmilka [50]

Answer:

on the surface of the cathode

6 0

1 year ago

0.023 M solution of perchloric acid

kogti [31]

The original question is to find the pH and the pOH of 0.023 M of perchloric acid.

Answer:
pH = 1.638
pOH = 12.362

Explanation:
1- getting the pH:
pH can be calculated using the following rule:
pH = -log[H+]
Since the given solution is an acid, this means that [H+] is the same as the concentration of the solution.
This means that:
[H+] = 0.023
Substitute in the above equation to get the pH as follows:
pH = -log[0.023]
pH = 1.638

2- getting the pOH:
We know that:
pH + pOH = 14
We have calculated that pH = 1.638.
Substitute in the above equation to get the pOH as follows:
pOH + 1.638 = 14
pOH = 14 - 1.638
pOH = 12.362

Hope this helps :)

5 0

2 years ago