Answer:
22.35 g of (NH₄)₃PO₄ will be produced by 7.5 g of ammonia.
Explanation:
H₃PO₄ + 3NH₃ → (NH₄)₃PO₄
H₃PO₄: 98 g/mol
NH₃: 17 g/mol
(NH₄)₃PO₄: 149 g/mol
17 g NH₃ _________ 1 mol
7.5 g NH₃ __________ x
x = 0.44 mol NH₃
3 mol NH₃ __________ 1 mol (NH₄)₃PO₄
0.44 mol NH₃ _________ y
y = 0.15 mol (NH₄)₃PO₄
1 mol (NH₄)₃PO₄ ____________ 149 g
0.15 mol (NH₄)₃PO₄ __________ z
z = 22.35 g (NH₄)₃PO₄
They have the same amount of particles.
If you convert 80g to moles, you will find that 80g of diatomic bromine is 1 mole.
