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Alchen [17]
3 years ago
9

After the Big Bang, which two elements were formed and became the "building blocks" for all other elements and molecules?

Chemistry
1 answer:
mylen [45]3 years ago
5 0
It would be hydrogen and helium :)

Since they are the most basic materials when galaxies and stars were born
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Which TWO of the following options are TRUE about atomic mass and mass number?
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Answer:

E - Atomic mass is calculated by weighted atomic average using all the isotope data available.

G - Mass number is equal to the sum of protons and electrons in an atom.

Explanation:

Take an element

\\ \bull\sf\longmapsto _{25}Mg^{12}

  • Mass no is 25 and atomic no is 12.
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You observe heat, light, and sound released by a chemical reaction. This reaction is (2 points)
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Exothermic reaction.
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If a gas occupies 4600 mL at 0.9 atm and 195°C, what is the new volume in ml
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Answer:

The new volume is 2415 mL

Explanation:

The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases.

Boyle's law says that the volume occupied by a given gas mass at constant temperature is inversely proportional to the pressure and is expressed mathematically as:

P * V = k

Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

\frac{V}{T} =k

Gay-Lussac's law indicates that when there is a constant volume, as the temperature increases, the gas pressure increases. And when the temperature is decreased, the gas pressure decreases. This can be expressed mathematically in the following way:

\frac{P}{T} =k

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

\frac{P*V}{T} =k

Having two different states, an initial state and an final state, it is true:

\frac{P1*V1}{T1} =\frac{P2*V2}{T2}

In this case:

  • P1= 0.9 atm
  • V1=4,600 mL= 4.6 L (being 1 L=1,000 mL)
  • T1= 195 °C= 468 °K (being 0°C=273°K)

The final state 2 is in STP conditions:

  • P2= 1 atm
  • V2= ?
  • T2= 0°C= 273 °K

Replacing:

\frac{0.9 atm*4.6L}{468K} =\frac{1 atm*V2}{273K}

Solving:

V2=\frac{0.9 atm*4.6L}{468K}*\frac{273K}{1 atm}

V2= 2.415 L =2,415 mL

<u><em>The new volume is 2415 mL</em></u>

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Answer:

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