Answer:
a)15077 W
b)20.2185 horse power
Explanation:
P=F*V
F=ma
a=Vf-VS/t
Vf=28m/s
t=5.2
a=28/5.2
a=5.384 m/s²
F=100kg*5.384m/s²
F=538.4 N
P=F*V
P=538.4N*28m/s
P=15077 W=20.2185 horse power
1W=0.00134 Horse power
From the law of the conservation of energy; the ratio of the total kinetic energy after the collision to the total kinetic energy before the collision must be 1.
<h3>What is momentum?</h3>
The term momentum is the product of mass and velocity. The principle of conservation of linear momentum states that total momentum before collision must be the same as the total momentum after collision thus the ratio of the total momentum after the collision to the total momentum before the collision must be 1.
Also, from the law of the conservation of energy; the ratio of the total kinetic energy after the collision to the total kinetic energy before the collision must be 1.
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Answer:
A)
B)
Explanation:
<u>Given:</u>
Length of the room 
Width of the room 
A) Let A be the area of the room

B)We will calculate uncertainty in each dimension
%uncertainty in length
%uncertainty in width =
The uncertainty in area will be sum of uncertainty in length and width
%uncertainty in Area= %uncertainty in length + %uncertainty in width
%uncertainty in Area
%uncertainty in Area=0.0106
Uncertainty in Area
There Area is
Answer:
The moment of inertia of the turntable about the rotation axis is 0.0225 kg.m²
Explanation:
Given;
radius of the turnable, r = 60 cm = 0.6 m
rotational kinetic energy, E = 0.25 J
angular speed of the turnable, ω = 45 rpm
The rotational kinetic energy is given as;

where;
I is the moment of inertia about the axis of rotation
ω is the angular speed in rad/s


Therefore, the moment of inertia of the turntable about the rotation axis is 0.0225 kg.m²
The wavelength of the emitted photon is(
)= 690nm
<h3>How can we calculate the wavelength of the emitted photon?</h3>
To calculate the wavelength of the photon we are using the formula,

Or,
We are given here,
= The energy difference between the two levels = 1. 8 ev=
C.
h= Planck constant =
Js.
c= speed of light =
m/s.
We have to find the wavelength of the emitted photon =
m.
Therefore, we substitute the known parameters in the above equation, we can find that,

Or,
Or,
m
Or,
=690 nm.
From the above calculation we can conclude that the wavelength of the emitted photon is 690nm.
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