Question

29.0g silver combine completely with 4.30g of sulfur to form a compound. what is the percent composition of this compound?

Answer 1

Answer:

Percentage of silver and sulphur in the compound  is 87.08% and 12.91%  respectively

Explanation:

Given:

Amount of silver = 29.0 g

Amount of sulphur= 4.30 g

To find:

Percent composition of the compound=?

Solution:

$\text { percent of compound }=\frac{\text { amount of element }}{\text { Total Molecule Mass }} \times 100$

Total Molecule mass = amount of silver + amount of sulphur

Total Molecule mass = 29+4.3  

Total Molecule mass = 33.3g

Percentage of silver:

$\text { Percentage of silver }=\frac{\text { amount of silver }}{\text { Total Molecule Mass }} \times 100$

=>$\frac{29.0}{33.3}\times100$

=>$0.8708 \times100$

=> 87.08%

Percentage of silver:

$\text { Percentage of silver }=\frac{\text {amount of suplhur}}{\text { Total Molecule Mass }} \times 100$

=>$\frac{4.30}{33.3}\times 100$

=>$0.1291\times 100$

=> 12.91%