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grandymaker [24]
3 years ago
9

5.4 When looking down the C{{TOP-HAT-MATH-TOKEN-0}}-C{{TOP-HAT-MATH-TOKEN-1}} bond in 2,3-dimethylbutane, what is the most stabl

e conformer
Chemistry
1 answer:
AURORKA [14]3 years ago
7 0

Answer:

The most stable conformer would be the anti-conformer when the substituent methyl groups are farthest away from each other.

Explanation:

Isomers are chemical compounds with the same molecular formula but with different molecular structures.

Conformers are a special type of isomers that produce different structures when the substituents of a Carbon-Carbon single bond (C-C) are rotated.

In 2,3 dimethyl butane, the substituent methyl groups are located around the second and third Carbon to Carbon single bond.

To achieve a stable configuration, the methyl group substituents need to be as far apart as possible (that is, in an anti-position) to minimise repulsion.

The closer the methyl groups are to each other, the more they repel each other and the more unstable the conformer becomes.

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Hello there!

In this case, according to the given information, it turns out possible for us to figure out the required net ionic equation by firstly writing out the complete molecular equation between aspirin and sodium acetate:

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C_9H_8O_4+C_2H_3O_2^-\rightarrow C_2H_4O_2+C_9H_7O_4^-

Regards!

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