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Setler79 [48]
3 years ago
6

Are outer planets gaseous

Physics
1 answer:
bija089 [108]3 years ago
6 0

Answer:

Yes

Explanation:

The four outer planets are all gas giants made primarily of hydrogen and helium. They have thick gaseous outer layers and liquid interiors.

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A wave traveling in a string has a wavelength of 35 cm, an amplitude of 8.4 cm, and a period of 1.2 s. what is the speed of this
kifflom [539]

The equation will be of the given statement:

y(x,t)  = (0.084)sin(18x - 5.2t)

<h3>What is Wavelength?</h3>

The distance a wave travels from one crest to another or from one trough to another is known as its wavelength (which may be an electromagnetic wave, a sound wave, or any other wave). The peak of the wave is called the crest, while the trough is its base.

<h3>According to the given information:</h3>

wavelength  = 35cm = .35m

amplitude A =  8.4 cm

Time  = 1.2s

The speed of this wave:

In the positive x direction, the wave is moving in a string. For these circumstances, we must write the wave equation.

When the wave is moving in the +x direction, the following general equation describes it:

Y = Asin( kx - wt )

A is amplitude

k is propagation constant

k = 2π/λ

k = 2π/0.35

k = 17.95 = 18m^-1

ω is angular frequency

ω = 2π/T

ω = 2π/1.2

ω = 5.23s^-1

The equation will be:

y(x,t)  = (0.084)sin(18x - 5.2t)

To know more about wavelength  visit:

brainly.com/question/13533093

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I understand that the question you are looking for is:

A wave traveling in a string in the positive x direction has a wavelength of 35 cm, an amplitude of 8.4 cm, and a period of 1.2 s. What is the wave equation (in base SI units) that correctly describes this wave

4 0
2 years ago
A 1.8-m uniform rod is being used to balance two buckets of paint. One pucket is full, but the other is mostly empty, and has on
Lisa [10]

Answer: 0.36 m

Explanation:

By definition, the x coordinate of the center of mass of the system obeys the following equation:

Xm = (m1x1 + m2x2 + …….+ mnxn) / m1+m2 +……+ mn

Neglecting the mass of the rod, and choosing our origin to be coincident with the location of the full bucket, we can write the following expression for the X coordinate of the center of mass (Assuming that both masses are aligned over the x-axis, so y-coordinates are zero):

Xm = 0.25 mb . 1.8 m / (1+0.25) mb

Simplifying mb, we get:

Xm= 0.36 m (to the right of the full bucket).

6 0
3 years ago
In the formula C12H22011 how many atoms and elements are there?
stiv31 [10]

Answer:

Explanation:

12 + 22 + 11 = 45

There are 45 atoms, and there are three elements: C, H, and O.

8 0
3 years ago
A resistor R, inductor L, and capacitor C are connected in series to an AC source of rms voltage ΔV and variable frequency. If t
Alexandra [31]

Answer:E=\frac{\pi R\left ( \Delta V\right )^2\sqrt{LC}}{\left ( R^2+\frac{9}{4}\left (\frac{L}{C} \right )\right )}

Explanation:

We know resonant frequency is given by

\omega_0=\frac{1}{\sqrt{LC}}

and the operating frequency is given by

\omega =2\omega_0=\frac{2}{\sqrt{LC}}

The capacitance reactance is given by

X_c=\frac{1}{\omega C}=\frac{\sqrt{LC}}{2C}=\frac{1}{2}\sqrt{\frac{L}{C}}

inductive reactance is given by

X_L=\omega L=\left ( \frac{2}{\sqrt{LC}}\right )L=2\sqrt{\frac{L}{C}}

Thus impedance is

Z=\left ( R^2+\left (X_L-X_C \right )^2 \right )^\frac{1}{2}

Z=\left ( R^2+\left (2\sqrt{\frac{L}{C}}-\frac{1}{2}\sqrt{\frac{L}{C}} \right )^2 \right )^\frac{1}{2}

Z=\left ( R^2+\frac{9}{4}\left ( \frac{L}{C} \right ) \right )^\frac{1}{2}

The average power delivered is

P_{avg.}=\frac{\Delta V^2}{Z}cos\phi =\frac{\left ( \Delta V\right )^2}{Z}\left (\frac{R}{Z} \right )

P_{avg.}=\frac{\left (\Delta V \right )^2R}{\left ( R^2+\frac{9}{4}\left (\frac{L}{C} \right )\right )}

Energy Delivered in one cycle is given by

E=P_{avg}T

E=\frac{\left (\Delta V \right )^2R}{\left ( R^2+\frac{9}{4}\left (\frac{L}{C} \right )\right )}\left ( \frac{2\pi }{\frac{2}{\sqrt{LC}}}\right )

E=\frac{\pi R\left ( \Delta V\right )^2\sqrt{LC}}{\left ( R^2+\frac{9}{4}\left (\frac{L}{C} \right )\right )}              

3 0
3 years ago
A cannonball is launched diagonally with an initial horizontal speed of 51.0m/s
OLEGan [10]

• initial horizontal speed: 51.0 m/s

• initial vertical speed: 24.0 m/s

• initial speed: √((51.0 m/s)² + (24.0 m/s)²) ≈ 56.4 m/s

• angle: tan(<em>θ</em>) = (24.0 m/s) / (51.0 m/s)   →   <em>θ</em> ≈ 25.2º

6 0
3 years ago
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