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3 years ago

Are outer planets gaseous

Physics

1 answer:

bija089 [108]3 years ago

6 0

Answer:

Yes

Explanation:

The four outer planets are all gas giants made primarily of hydrogen and helium. They have thick gaseous outer layers and liquid interiors.

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With each beat of your heart the aortic valve opens and closes. The valve opens and closes very rapidly, with a peak velocity as

Nonamiya [84]

Answer:

|Δf| = 37.3 kHz

Explanation:

given,

peak velocity = 4 m/s

speed of the sound = 1500 m/s

frequency = 7 MHz

$v = C\dfrac{\pm \dlta f}{2 f_0}$

$\delta f = \pm 2 f_0 (\dfrac{V}{C})$

$\delta f = \pm 2\times 7 (\dfrac{4}{1500})$

$=\pm 0.0373 MHz$

= 37.3 kHz

|Δf| = 37.3 kHz

hence, frequency shift between the opening and closing valve is 37.3 kHz

4 0

3 years ago

When the temperature of 2.35 m^3 of a liquid is increased by 48.5 degrees Celsius, it expands by 0.0920 m^3. What is its coeffic

Nuetrik [128]

Answer:

$8.1\cdot 10^{-4} C^{-1}$

Explanation:

The volumetric expansion of the liquid is given by

$\Delta V=\alpha V_0 \Delta T$

where

$\alpha$ is the coefficient of volume expansion

$V_0$ is the initial volume

$\Delta T$ is the change in temperature

For the liquid in this problem,

$V_0 = 2.35 m^3\\\Delta T=48.5^{\circ}C\\\Delta V=0.0920 m^3$

So we can solve the equation to find $\alpha$ :

$\alpha=\frac{\Delta V}{V_0 \Delta T}=\frac{(0.0920 m^3)}{(2.35 m^3)(48.5^{\circ}C)}=8.1\cdot 10^{-4} C^{-1}$

7 0

4 years ago

Someone pls help!! Right now :(

julsineya [31]

It would be yes, once they pull the parachute they start to accelerate upwards

4 0

3 years ago

How do I find the tension? its supposed to be in the mid 40s

babunello [35]

Answer:

a = 2.3 m/s²

T = 45 N

Explanation:

Draw a free body diagram for each mass.

For the mass on the incline, there are four forces:

Weight force mg pulling down.

Normal force N perpendicular to the incline.

Friction force Nμ pushing down the incline.

Tension force T pulling up the incline.

For the hanging mass, there are two forces:

Weight force Mg pulling down.

Tension force T pulling up.

Sum of the forces on the hanging mass in the -y direction:

∑F = ma

Mg − T = Ma

T = Mg − Ma

Sum of the forces on the sliding mass in the perpendicular direction:

∑F = ma

N − mg cos θ = 0

N = mg cos θ

Sum of the forces on the sliding mass in the parallel direction:

∑F = ma

T − mg sin θ − Nμ = ma

Substitute:

Mg − Ma − mg sin θ − mgμ cos θ = ma

Mg − mg (sin θ + μ cos θ) = ma + Ma

Mg − mg (sin θ + μ cos θ) = (m + M) a

a = [ Mg − mg (sin θ + μ cos θ) ] / (m + M)

Plug in values:

a = [ 6.0×9.8 − 5.0×9.8 (sin 30° + 0.20 cos 30°) ] / (5.0 + 6.0)

a = 2.3 m/s²

Now find tension:

T = Mg − Ma

T = 6.0×9.8 − 6.0×2.3

T = 45 N

3 0

4 years ago

Which force diagram accurately represents a satellite in orbit around Earth?

Anit [1.1K]

Answer:

First choice

Explanation:

A satellite in orbit around Earth experiences only one force: the gravitational attraction exerted by the Earth on it. This force is labelled with $F_g$ . In space, there are no other forces acting on the satellite.

The force of gravity acts as centripetal force, "pulling" the satellite towards the centre of its circular orbit. The inertia of the satellite (which has an initial velocity) tends to keep it moving straight, so the combination of these two effects (inertia and force of gravity) results into the circular motion of the satellite.

5 0

3 years ago

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