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2 years ago

Light hits a mirror at a 45Â° angle. It will be reflected at an angle _____.

Physics

1 answer:

Eddi Din [679]2 years ago

6 0

It will be equal to 45Â°

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The trajectory of a projectile always ________________. The trajectory of a projectile always ________________. is a straight li

jenyasd209 [6]

Answer:

curves downward, below the initial velocity vector.

Explanation:

Projectile launches are generally divided into two types: the oblique throw and the free fall. The free fall of bodies consists of throwing or abandoning projectiles from a hill or any unevenness that has a height in relation to a frame (usually the ground), while the oblique launch consists of launching a projectile at an angle. any relative to a frame (usually the ground).

Regardless of the type, when reading the paragraph above, we can say that the trajectory of a projectile will always be curved down and below the initial velocity vector.

6 0

3 years ago

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8. What is the mass of an object if a force of 34 N produces an acceleration of 4 m/s/s?

coldgirl [10]

Answer:

<h3>The answer is 8.5 kg</h3>

Explanation:

The mass of the object can be found by using the formula

$m = \frac{f}{a} \\$

where

f is the force

a is the acceleration

So we have

$m = \frac{34}{4} = \frac{17}{2} \\$

We have the final answer as

Hope this helps you

7 0

2 years ago

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Name 2 common methods of polymerization.

navik [9.2K]

Answer: Addition polymerization & Condensation polymerization

6 0

3 years ago

According to the rule of 72 and about how many years will $78 be worth $39 if the rate of inflation is 5.8%

Monica [59]

The answer is 12.4 years

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3 years ago

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It has been suggested, and not facetiously, that life might have originated on Mars and been carried to Earth when a meteor hit

damaskus [11]

Answer:

$a=3125000 m/s^2\\a=3.125*10^6 m/s^2$

Acceleration, in m/s, of such a rock fragment = $3.125*10^6m/s^2$

Explanation:

According to Newton's Third Equation of motion

$V_f^2-V_i^2=2as$

Where:

$V_f$ is the final velocity

$V_i$ is the initial velocity

a is the acceleration

s is the distance

In our case:

$V_f=V_{escape}, V_i=0,s=4 m$

So Equation will become:

$V_{escape}^2-V_i^2=2as\\V_{escape}^2-0=2as\\V_{escape}^2=2as\\a=\frac{V_{escape}^2}{2s}\\a=\frac{(5*10^3m)^2}{2*4}\\a=3125000 m/s^2\\a=3.125*10^6 m/s^2$

Acceleration, in m/s, of such a rock fragment = $3.125*10^6m/s^2$

5 0

2 years ago