Answer:
the horizontal force acting on rod is - 25.909 N
veritical force is 25.48 N
Explanation:
Given data:
mass of rod is m 2.6 kg
length of rod is 1.5 m
Hinge distance from the wire is 0.70 m
Apply torque law about hinge

Tension in the wire is
![T = \frac{[\frac{1.5}{2} cos 28 ]2.6 \times 9.8}{0.70}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B%5B%5Cfrac%7B1.5%7D%7B2%7D%20cos%2028%20%5D2.6%20%5Ctimes%209.8%7D%7B0.70%7D)
= -25.909 N
the horizontal force acting on rod is
Fx = T
FX = - 25.909 N
vertical force is
Fy = mg

C because If it still moving in a circle it’s not going to change.
I think its either b. or d. i know its not a. It might be B. hope this helps?
Answer: thermal conductivity
Answer:
The natural frequency will be 228.11 rad/sec
Explanation:
We have given Inductance L = 0.048 Henry
And the capacitance C = 0.0004 farad
We have to find natural frequency
When only inductor and capacitor is present in the circuit then it is known as LC circuit and Natural frequency of LC circuit is given by 
So the natural frequency will be 228.21