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Ratling [72]
3 years ago
8

Identify the features that are unique to some sedimentary rocks.

Physics
1 answer:
mr Goodwill [35]3 years ago
3 0
(f). Characteristics<span> of </span>Sedimentary Rocks<span>. </span>Sedimentary rocks<span> can be categorized into three groups based on sediment type. Most </span>sedimentary rocks<span> are formed by the lithification of weathered </span>rock<span> debris that has been physically transported and deposited.</span>
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If it requires 7.0 JJ of work to stretch a particular spring by 1.7 cmcm from its equilibrium length, how much more work will be
Lynna [10]

Answer:

Explanation:

First of all, well calculate the spring constant k

K = 2Ei/x^2

Where Ei = initial work required

x = initial stretch length

k = 2×7/0.017^2 = 48443J/m^2

Now work done in stretching it to 5.3cm (1.7 + 3.6) or 0.053m

EF = kx^2/2

48443 × 0.053^2/2 = 68J

Work done in stretching additional 3.6cm is equal to

68J-7J = 61J

3 0
4 years ago
A simple generator has a square armature 9.0 cm on a side. The armature has 95 turns of 0.59-mm-diameter copper wire and rotates
Marrrta [24]

Answer:

f = 3.102 Hz

Explanation:

In this case you have that the required voltage is the maximum induced emf produced by the rotating generator.

In order to calculate the frequency of rotation of the generator that allows one to obtain 12.0V you use the following formula:

emf_{max}=NBA\omega    (1)

N: turns of the armature = 95

B: magnitude of the magnetic field = 0.800T

A: area of the square armature = (9.0cm)^2 = (0.09m)^2 = 8.1*10^-3 m^2

emf_max = 12.0V

w: angular frequency

you solve the equation (1) for w:

\omega=\frac{emf_{max}}{NBA}=\frac{12.0V}{(95)(0.800T)(8.1*10^{-3}m^2)}\\\\\omega=19.49\frac{rad}{s}

Then, the frequency is:

f=\frac{\omega}{2\pi}=\frac{19.49rad/s}{2\pi}=3.102Hz

7 0
3 years ago
3. A Japanese bullet train slows from a speed of 50 m/sec to a speed of 40 m/sec in 500m.
Triss [41]

Answer:

-0.9 m/s²

Explanation:

Given:

Δx = 500 m

v₀ = 50 m/s

v = 40 m/s

Find: a

v² = v₀² + 2aΔx

(40 m/s)² = (50 m/s)² + 2a (500 m)

a = -0.9 m/s²

6 0
4 years ago
decibels are a measure of sound on a logarithmic scale, where the number in front of the zero represents the number of powers of
Korolek [52]

The  power ratio of a washing machine at 80 decibels is 10⁸ or 100,000,000.

<h3>What is the power ratio of a sound of 80 decibels?</h3>

Sound is a form of disturbance created by the vibrations of the medium and which travels across the medium in wave form.

A measure of sound intensity is decibels.

Decibels are a measure of sound on a logarithmic scale, where the number in front of the zero represents the number of powers of 10.

Therefore, the power ratio of a washing machine at 80 decibels will be 10⁸.

In conclusion, sound are vibrations which transmit energy.

Learn more about sound at: brainly.com/question/1199084

#SPJ1

5 0
2 years ago
How did the social structure of ancient Rome affect the lives of its people?
Neporo4naja [7]

Answer:

                 

Explanation:

5 0
3 years ago
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