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Levart [38]
3 years ago
5

1.)The product of five and a number x

Mathematics
2 answers:
Novay_Z [31]3 years ago
8 0
He is absolutely correct i worked it out
lina2011 [118]3 years ago
4 0

Answer:

1.) 5x

2.) 2/3x^2

3.) 53 + x

4.) 32d

5.) 19 + 2x

1.) The product of five and a number x

2.) The product of twenty four and a number x

3.) The sum of a number y and nineteen

4.) The difference of a number x and two

4.) A number y divided by two / The quotient of a number y and two

Explanation:

Keep in mind the following definitions:

  • Sum means addition +
  • Difference means subtraction -
  • Product means multiplication *
  • Square means ^2

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The bases of a right prism are isosceles trapezoids with bases of 10 ft and 18 ft
likoan [24]

Answer:

540 ft^2.

Step-by-step explanation:

The area of the trapezoid = h/2 (10 + 18) = 14h.

By Pythagoras the height h = √(5^2 - 4^2) = 3.

So the area of the 2 trapezoidal bases = 2 * 14*3

= 84 ft^2.

Now we calculate the area of the four lateral rectangular sides:

= 10*12 + 18*12 + 2*5*12

= 456 ft^2.

Total area =  456 + 54

= 540 ft^2.

4 0
3 years ago
The sum of three numbers is 62. The second number is equal to the first number diminished by 4. The third number is four times t
alexdok [17]
Let the three numbers be x, y and z respectively, then
x + y + z = 62 . . . (1)
y = x - 4 . . . (2)
z = 4x . . . (3)

The above three expressions could be used to represent the numbers.

Solving the three equations, putting (2) and (3) into (1) gives
x + x - 4 + 4x = 62
6x - 4 = 62
6x = 62 + 4 = 66
x = 66/6 = 11
x = 11.
y = 11 - 4 = 7
z = 4(11) = 44

x = 11, y = 7, z = 44.
3 0
3 years ago
Read 2 more answers
Find the area of an equilateral triangle (regular 3-gon) with the given measurement.
erica [24]
Answer is 36 hope this helps
7 0
3 years ago
Write an equation of the line that passes through the given points (1 , 1.5) and (2, 3.5)
Nitella [24]

Answer:

y=2x-0.5

Step-by-step explanation:

typically, the equation of the line is written in slope intercept form, which is y=mx+b, where m is the slope and b is the y intercept

first, we need to find the slope (m) of the line

the formula for slope calculated from two points is given as (y2-y1)/(x2-x1)

we have two points: (1,1.5) and (2,3.5) and we can label them

x1=1

y1=1.5

x2=2

y2=3.5

now plug into the formula:

m=(3.5-1.5)/(2-1)

m=2/1

m=2

the slope of the line is 2

here's our equation so far:

y=2x+b

now we need to find b

since the line will pass through the points (1, 1.5) and (2, 3.5), we can plug either one of them into the equation to solve for

Let's use (1, 1.5)

substitute 1.5 as y and 1 as x

1.5=2(1)+b

1.5=2+b

subtract 2 from both sides

-0.5=b

therefore, our equation is:

y=2x-0.5

hope this helps!

5 0
3 years ago
Use the given qualitative data to construct the relative frequency distribution.
ikadub [295]

Answer:

Category                         Relative Frequency

male survivors                           17.3%

males who died                          63.7 %

Female survivors                        15.1 %

Females who died                       3.8%

Step-by-step explanation:

  • The relative frequency is the proportion of the number of times the event occurs to the total number of trials.

Given : Total people on ship = 2274

Number of male ​survivors = 394

⇒ Relative Frequency of male ​survivors =\dfrac{394}{2274}

In percent , \dfrac{394}{2274}\times100\approx17.3\%

Number of males who​ died =1449

⇒ Relative Frequency of male ​who​ died =\dfrac{1449}{2274}

In percent , \dfrac{1449}{2274}\times100\approx63.7\%

Number of female​ survivors =344

⇒ Relative Frequency of female​ survivors =\dfrac{344}{2274}

In percent , \dfrac{344}{2274}\times100\approx15.1\%

Number of females who died = 87

⇒ Relative Frequency of females who died =\dfrac{87}{2274}

In percent , \dfrac{87}{2274}\times100\approx3.8\%

Hence, the complete table would be :

Category                         Relative Frequency

male survivors                           17.3%

males who died                          63.7 %

Female survivors                        15.1 %

Females who died                       3.8%

8 0
3 years ago
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