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ser-zykov [4K]
3 years ago
10

which of these statements best compares the processes by which energy is produced in the sun and nuclear power plants? a. atoms

fuse in the sun, but atoms break up in nuclear power plants. b. atoms break up in the sun, but atoms fuse in nuclear power plants. c. atoms of elements in the sun expand to emit heat and nuclear energy. d. atoms of elements in the sun contract to emit heat and nuclear energy.
Physics
2 answers:
11Alexandr11 [23.1K]3 years ago
5 0

Answer:

A. Atoms fuse in the sun, but break up in nuclear power plants.

Explanation:

In the Sun occurs a phenomenon called Nuclear Fusion, there a massive fusion reaction is constantly occurring with the presence of hydrogen and helium.

On the other hand, nuclear power plants collide neutrons against uranium atoms to split them. So, this split provide neutrons from uranium, which collide with other atoms causing a chain reaction, releasing high power energy.

Harlamova29_29 [7]3 years ago
3 0
A. atoms fuse in the sun, but atoms break up in nuclear power plants.

The process in the Sun is a Fusion Process, atoms are fused, while the process in nuclear power plant is a Fission Process, atoms break up. 
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Starting from rest, a disk rotates about its central axis with constant angular acceleration. in 6.00 s, it rotates 44.5 rad. du
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b. Since acceleration is constant, the average angular velocity is

\omega_{\rm avg}=\dfrac{\omega_f+\omega_i}2=\dfrac{\omega_f}2

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\omega=\alpha t

so we have

\omega_f=\left(2.47\dfrac{\rm rad}{\mathrm s^2}\right)(6.00\,\mathrm s)=14.8\dfrac{\rm rad}{\rm s}

making the average velocity

\omega_{\rm avg}=\dfrac{14.8\frac{\rm rad}{\rm s}}2=7.42\dfrac{\rm rad}{\rm s}

Another way to find the average velocity is to compute it directly via

\omega_{\rm avg}=\dfrac{\Delta\theta}{\Delta t}=\dfrac{44.5\,\rm rad}{6.00\,\rm s}=7.42\dfrac{\rm rad}{\rm s}

c. We already found this using the first method in part (b),

\omega=14.8\dfrac{\rm rad}{\rm s}

d. We already know

\theta=\dfrac\alpha2t^2

so this is just a matter of plugging in t=12.0\,\mathrm s. We get

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Or to make things slightly more interesting, we could have taken the end of the first 6.00 s interval to be the start of the next 6.00 s interval, so that

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Answer:

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