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alexdok [17]
3 years ago
5

The formula for the compound ammonium chloride?

Chemistry
1 answer:
Oliga [24]3 years ago
8 0
The formula for the compound ammonium chloride is NH4Cl
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A solution is made by mixing 12.54 grams of NaNO3 with enough water to make 2.5 L of solution. What is the molarity?
Alex

Answer:

is there a table or an equation for that ??

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3 years ago
When data does not support your hypothesis in an experiment, you must revise what
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6 0
4 years ago
How many grams of zinc would be required to produce 9.65g of zinc hydroxide
Effectus [21]

The question is incomplete, here is the complete question:

How many grams of zinc would be required to produce 9.65g of zinc hydroxide

Zn+2MnO₂+H₂O→Zn(OH)₂+Mn₂O₃

<u>Answer:</u> The mass of zinc required is 6.35 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of zinc hydroxide = 9.65 g

Molar mass of zinc hydroxide = 99.4 g/mol

Putting values in equation 1, we get:

\text{Moles of zinc hydroxide}=\frac{9.65g}{99.4g/mol}=0.0971mol

The given chemical equation follows:

Zn+2MnO_2+H_2O\rightarrow Zn(OH)_2+Mn_2O_3

By Stoichiometry of the reaction:

1 mole of zinc hydroxide is produced from 1 mole of zinc

So, 0.0971 moles of zinc hydroxide will be produced from = \frac{1}{1}\times 0.0971=0.0971mol of zinc

Now, calculating the mass of zinc from equation 1, we get:

Molar mass of zinc = 65.4 g/mol

Moles of zinc = 0.0971 moles

Putting values in equation 1, we get:

0.0971mol=\frac{\text{Mass of zinc}}{65.4g/mol}\\\\\text{Mass of zinc}=(0.0971mol\times 65.4g/mol)=6.35g

Hence, the mass of zinc required is 6.35 grams

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3 years ago
How many molecules are contained in a 3.36 mole sample of NH3?
denpristay [2]

3.36 \times (6.02 \times  {10}^{23} ) = 2.0227 \times  {10}^{24}
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