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blsea [12.9K]
3 years ago
6

One way to measure temperature in some applications is to monitor the gas pressure in a rigid, closed container. What is the tem

perature of such a vessel, calibrated to read 1.000 atm at STP, if the pressure reads 1.250 atm?
Chemistry
1 answer:
julia-pushkina [17]3 years ago
6 0

Answer:

296.43 K is the temperature of a vessel when pressure reads 1.250 atm.

Explanation:

At STP, when pressure is 1.000 atm the value of temperature is 273,15 K.

If the pressure at temperature T reads as 1.250 atm.

P_1=1.000 atm, T_1=298.15K

P_2=1.250 atm,T_2=?

Applying Gay Lussac's law:

\frac{P_1}{T_1}=\frac{P_2}{T_2} (At constant volume)

\frac{1.000 atm}{273.15 K}=\frac{1.250 atm}{T_2}

T_2=296.43 K

296.43 K is the temperature of a vessel when pressure reads 1.250 atm.

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Answer:

The answer is 12.35

Explanation:

From the question we are given that the concentration of H^{+} is 8.1 * 18^{-6}M

 Generally The rate equation is given as

                                                           K_{w} = [H^{+} ][OH^{-} ]

and K_{w} the rate constant has a value 1 * 10^{-14}

     Substituting and making [OH^{-}] the subject we have

                                                 [OH^{-} ] = \frac{1 * 10^{-14}}{[H^{+}]} = \frac{1 * 10^{-14}}{8.1 *10^{-6}} =1.235 * 10^{-9}

                                                  [OH ^ {-}] = 1.235 * 10^{-9}M

                            Multiply the value by 10^{10} as instructed from the question we have  

                       Answer =   1.235 * 10 ^{-9} * 10^{10} = 12.35

Hence the answer in 2 decimal places is 12.35

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