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blsea [12.9K]
3 years ago
6

One way to measure temperature in some applications is to monitor the gas pressure in a rigid, closed container. What is the tem

perature of such a vessel, calibrated to read 1.000 atm at STP, if the pressure reads 1.250 atm?
Chemistry
1 answer:
julia-pushkina [17]3 years ago
6 0

Answer:

296.43 K is the temperature of a vessel when pressure reads 1.250 atm.

Explanation:

At STP, when pressure is 1.000 atm the value of temperature is 273,15 K.

If the pressure at temperature T reads as 1.250 atm.

P_1=1.000 atm, T_1=298.15K

P_2=1.250 atm,T_2=?

Applying Gay Lussac's law:

\frac{P_1}{T_1}=\frac{P_2}{T_2} (At constant volume)

\frac{1.000 atm}{273.15 K}=\frac{1.250 atm}{T_2}

T_2=296.43 K

296.43 K is the temperature of a vessel when pressure reads 1.250 atm.

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Answer:

127.3° C, (This is not a choice)

Explanation:

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ΔT = Kb . m . i

Where:

ΔT = T° boling of solution - T° boiling of pure solvent

Kb = Boiling constant

m = molal (mol/kg)

i = Van't Hoff factor (number of particles dissolved in solution)

Water is not a ionic compound, but we assume that i = 2

H₂O →  H⁺  +  OH⁻

T° boling of solution - 118.1°C =  0.52°C . m . 2

Mass of solvent =  Solvent volume / Solvent density

Mass of solvent = 500 mL / 1.049g/mL → 476.6 g

Mol of water are mass / molar mass

76 g / 18g/m = 4.22 moles

These moles are in 476.6 g

Mol / kg = molal → 4.22 m / 0.4766 kg = 8.85 m

T° boling of solution =  0.52°C . 8.85 m . 2 + 118.1°C =  127.3°C

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