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siniylev [52]
2 years ago
5

Please help me order these bonds

Chemistry
1 answer:
olya-2409 [2.1K]2 years ago
4 0

Answer:

From least polar covalent to most polar covalent;

S-I< Br-Cl < N-H< Te-O

From most ionic to least ionic

Cs-F> Sr-Cl> Li- N> Al-O

Explanation:

Electro negativity is the ability of an atom in a bonding situation to attract the electron pair of a bond towards itself.

Electro negativity difference between two atoms determines the nature of bond existing between any two atoms. When this difference is large, an ionic bond exists in the compound. However, an intermediate difference in electro negativity implies the existence of a polar covalent bond.

Hence, going by electro negativity differences as mentioned in the question, the bonds in the answer were arranged in order of increasing polar covalent nature or decreasing ionic nature as shown.

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Answer:

a)- Se, S, O

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Explanation:

We can solve this problem by looking at the Periodic Table. In a group, electronegativity increases from bottom to top; whereas in periods it increases from left to right.

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a. Se, O, S ⇒ order: Se, S, O

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They are in the same period. Na is at the left, followed by P and Cl is nearest the right.

c. Cl, S, F ⇒ order: S, Cl, F

P and Cl are in the same period, and P is at the left, so it has the lowest electronegativity. F is in the same group of Cl, but at the top. F has the highest electronegativity.

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