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timurjin [86]
3 years ago
9

In an electron-dot symbol of an element, the dots are used to represent ________.

Chemistry
1 answer:
Anit [1.1K]3 years ago
6 0

Answer:

Valence electrons.

Explanation:

Hello,

In this case, the electron dot structure is widely known for representing the valence electrons as dots placed around the chemical symbol and they are defined as the electrons configured at the outermost shell of the studied atom. Commonly, electrons are placed up to two on each side of the elemental symbol for a maximum of eight. For instance, sodium has one valence electron, sulfur has six valence electrons, helium has eight valence electrons and so on. Valence electrons are known to be dependent of the electron configuration.

Best regards.

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Which step in the scientific method is conducted before a controlled experiment?
ycow [4]
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You have 55 grams of glucose(C6H12O6). How many grams of oxygen do you have?
zubka84 [21]

Answer:

Mass of oxygen in glucose = 29.3g

Explanation:

Mass of glucose given is 55grams.

We are to find the mass of oxygen in this compound.

In the compound we have 6 atoms of oxygen.

Solution

To find the mass of oxygen in glucose, we calculate the formula mass of glucose. We now divide the formula mass of the oxygen atom with that of the glucose and multiply by the given mass to find the unkown mass.

Atomic mass of C = 12g

                           H = 1g

                           O = 16g

Formula mass of C₆H₁₂O₆ = {(12x6) + (1x12) + (16x6)} = 180

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                                                  = \frac{96}{180} x 55

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8 0
3 years ago
A 250.0-ml sample of ammonia, nh3 (g), exerts a pressure of 833 torr at 42.4 °c. what mass of ammonia is in the container
Lelu [443]
To solve this, let's assume ideal gas behavior.

PV=nRT
Let's solve for n. Convert units to SI units first.

Pressure = 833 torr(101325 Pa/760 torr) = 111,057.53 Pa
Volume = 250 mL(1 L/1000 mL)(1 m³/1000 L) = 2.5×10⁻⁴ m³
Temperature = 42.4 + 273 = 315.4 K

n = (8,314 J/mol·K)(315.4 K)/(111057.53 Pa)(2.5×10⁻⁴ m³)
n = 94.45 mol

The molar mass of ammonia is 17.031 g/mol.
Mass = 94.45*17.031 = <em>1,608.51 g ammonia</em>


6 0
3 years ago
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