Answer:
Making a vertical vector, we have a starting point at (-5,2) and an end point at (5,2) that will give us a vector of magnitude of 10 units.
Explanation:
In order to make vectors that have a magnitude of 10 units, the distance between the starting and ending points must be equal to 10.
The easiest way is to set points on either an horizontal or vertical line to make horizontal or vertical vectors.
We can have starting point at (-5,2) and then move up 10 units so we will be at the ending point (5,2), thus the distance between them is 10 units so the vector has a magnitude of 10 units.
We can verify that using the formula for the magnitude which requires first to find the vector.
So for the points we have
We can work with each component, for the x component we have 5-(-5) which give us 10 and for the y component we have 2-2 which give us 0, so the vector is
Thus its magnitude is
Thus we have verified our vector has a length 10.
Hey there!
I believe the answer is A. The boiling temperature did not change
Hope this helps you!
God bless ❤️
xXxGolferGirlxXx
Answer:
The mass of the block of ice is 90.91 kg.
Explanation:
The expression for the equation of motion is as follows;
Here, u is the initial speed, a is the acceleration, t is the time and s is the distance.
Calculate the acceleration of the given block.
Put t= 5 s, s= 11 m and u= 0 in the above expression.
The expression for the force in terms of mass and acceleration is as follows;
F= ma
Here, F is the force and m is the mass.
Put F= 80 N and .
80= m(0.88)
m=90.91 kg
Therefore, the mass of the block of ice is 90.91 kg.
Answer:
Acceleration,
Explanation:
It is given that,
Mass of Gary, m = 80.5 kg
Mass of his bicycle, m' = 13.7 kg
Net unbalanced force acting on him, F = 9.86 N
Let a is the value of acceleration. Both cycle and Gary will move with same acceleration. Using the second law of motion to find it as :
or
So, the value of acceleration of the Gary and bicycle is . Hence, this is the required solution.
Answer:
-5 m/s
Explanation:
The linear velocity of B is equal and opposite the linear velocity of E.
vB = -vE
vB = -ωE rE
10 m/s = -ωE (12 m)
ωE = -0.833 rad/s
The angular velocity of E is the same as the angular velocity of D.
ωE = ωD
ωD = -0.833 rad/s
The linear velocity of Q is the same as the linear velocity of D.
vQ = vD
vQ = ωD rD
vQ = (-0.833 rad/s) (6 m)
vQ = -5 m/s