Formula for orbital speed, v = √(GM/R)
Where G is the universal gravitational constant, M = Central Mass,
R = Distance between centers of Mass.
Given. v = 68 m/s, M = ? , R = 410 km = 410000 m., G = 6.674 * 10⁻¹¹ Nm²/kg²
68 = √(GM/R)
68 = √(6.674 * 10⁻¹¹ * M/410000)
68² = (6.674 * 10⁻¹¹ * M)/410000
(68² * 410000) / 6.674 * 10⁻¹¹ = M
2.84 × 10¹⁹ = M
Mass of Planet Y = 2.84 × 10¹⁹ kg
Answer:
option C
Explanation:
given,
mass of the three planet is same
radius of the planets are
R₁ > R₂ > R₃
expression of escape velocity

G is the gravitational constant
M is the mass of the planet
R is the radius of the planet
from the above expression we can clearly conclude that the escape velocity is inversely proportional to the radius of the Planet.
radius of planet increases escape velocity decreases.
Hence planet 3 has the smallest radius so the escape velocity of the third planet will be maximum.
The correct answer is option C
Answer: choices a and b
Explanation:
Telescope can be defined as am optical instrument which is designed to observe the distant objects clear and nearer. It comprises of arrangement of lenses which allow the rays of light to be collected. The collected light is focused and the image so produced is magnified in the form of an image. The telescopes are prepared and manufactured on mountains top as this will help in preventing the distortion of light obtain from the star due to the fluctuation of air mass in the atmosphere. The atmospheric distortion affects the resolution, and affects the vision. The atmospheric pressure is low at the mountain tops so it will help in better observation of the sky.
Answer:
There is absolutely No relationship between the weight of an object (which is constant) and the frictional force. If a block is sliding on a surface, that surface will be exerting a force on the block. That force can be resolved into a component parallel to the surface (which we call the frictional component), and a component perpendicular to the surface (called the normal component). For many situations, we find experimentally that the frictional component is approximately proportional to the normal component. The frictional component divided by the normal component is defined to be a quantity called the coefficient of kinetic or sliding friction. The coefficient of kinetic friction obviously depends on the nature of the surfaces involved. The normal component on an object can be decreased if you pull in the direction of the normal component (the weight does not change). However pulling this way on the object not only decreases the normal component, but it also decreases the frictional component since they are proportional. This is why it is easier to slide something if you pull up on it while you push it. If you push down, the normal and frictional components increase so it is harder to slide the object. The weight of an object is the downward force exerted by Earth’s gravity on that object, and it does not change no matter how you push or pull on the object.
Answer:
I dont see a picture where is it?
Explanation:
I cannot see anything L question Luestion