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maxonik [38]
3 years ago
6

Which is a proper description of chemical equilibrium?

Chemistry
1 answer:
serg [7]3 years ago
3 0
D) because both reactions are occurring at the same rate. They are not equal but their concentrations are constant.
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HURRY PLS! A chemical reaction takes place in which energy is released. Arrange the reaction’s characteristics in order from sta
belka [17]

Answer:

The difference between the energy of the reactants and the energy of the products is called the enthalpy change (∆H) of the reaction. For an exothermic reaction, the enthalpy change is always negative. In an endothermic reaction, the products are at a higher energy than the reactants.

Explanation:

7 0
3 years ago
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Carbon reacts with oxygen to produce carbon dioxide (CO2).
Jobisdone [24]
2 different elements- carbon and oxygen.............................
3 0
3 years ago
What mass of CO2 can be produced from the decomposition of 4.8 moles of Fe2(CO3)3?
gavmur [86]

Answer: 633.6 g of CO_2 can be produced from the decomposition of 4.8 moles of Fe_2(CO_3)_3

Explanation:

The balanced chemical equation for decomposition of Fe_2(CO_3)_2 is :

Fe_2(CO_3)_2\rightarrow Fe_2O_3+3CO_2

According to stoichiometry :

1 mole of Fe_2(CO_3)_2 produce = 3 moles of CO_2

Thus 4.8 moles of Fe_2(CO_3)_2 will rproduce=\frac{3}{1}\times 4.8=14.4moles  of CO_2

Mass of CO_2=moles\times {\text {Molar mass}}=14.4moles\times 44g/mol=633.6g

Thus 633.6 g of CO_2 can be produced from the decomposition of 4.8 moles of Fe_2(CO_3)_3

7 0
4 years ago
A reaction of importance in the formation of smog is that between ozone and nitrogen monoxide described by O3(g)+NO(g)⟶O2(g)+NO2
julsineya [31]

Answer:

Initial rate of reaction is 2.07\times 10^{-3}M.s^{-1}.

Explanation:

It is a second order reaction.

Initial rate of reaction = k[O_{3}]_{0}[NO]_{0}   , where k is rate constant, [O_{3}]_{0} is the initial concentration of O_{3} and [NO]_{0} is the initial concentration of NO.

Here, k = 4.09\times 10^{6}M^{-1}.s^{-1}, [O_{3}]_{0}=5.84\times 10^{-6}M and [NO]_{0}=8.65\times 10^{-5}M

So, initial rate of reaction = (4.09\times 10^{6}M^{-1}.s^{-1})\times (5.84\times 10^{-6}M)\times (8.65\times 10^{-5}M)

= 2.07\times 10^{-3}M.s^{-1}

So, initial rate of reaction is 2.07\times 10^{-3}M.s^{-1}

8 0
3 years ago
Devise a temperature scale, abbreviated g, for which the magnitude of the ideal gas constant is 1.00 j g–1 mol–1 .
melisa1 [442]

The value of ideal gas constant (R) in Joule is 8.314 Joule Kelvin^{-1}mol^{-1}. Now the given expression is 1.00 J. gg^{-1}.mole^{-1}. Where the g represent the temperature. Thus the abbreviated g must have the value 8.314 to satisfy the original value. Thus the temperature scale will be 1 kelvin = 8.314 g. Now 1 kelvin  = -272.15°C or in terms of abbreviation of g we can write -272.15 °C = 8.314g, or, 1°C  = (-) \frac{8.314}{272.15}=0.030g. Thus the temperature scale of the g scale is 1 kelvin (K) = 8.314g and 1°C = 0.030 g.  

7 0
4 years ago
Read 2 more answers
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