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ankoles [38]
3 years ago
8

Does the reaction of hydrogen produce any products that negatively affect the environment?

Chemistry
2 answers:
sashaice [31]3 years ago
5 0

Answer:

The reaction of hydrogen doesn’t produce any products that negatively affect the environment. The reaction emits only water vapor (H2O).

On Plato!!!

Explanation:

klasskru [66]3 years ago
3 0

The answer is NO. During combustion of hydrogen, water is produced as an end product. The chemical formulae for combustion of hydrogen are:

2H2 + O2 -->2 H2O

another advantage is that the whole of the fuel load is combusted hence little wastage. This has made the fuel advantageous in its use as rocket fuel since there is no baggage fuel.


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Aluminum can react with oxygen gas to produce aluminum oxide (Al¿OÀ). What type of reaction is this?
nadya68 [22]
B.. it is a combination reaction... A + B--> AB
3 0
3 years ago
A chemist has a small amount of compound ( b.p. = 65 oC) that must be fractionally distilled. Yet, the Chemist does not want to
koban [17]

Answer:

The chemist can either:

a. Use a small fractionation apparatus.

b. Add a compound with a much higher boiling point.

Explanation:

Using a smaller fractionation apparatus or Vigreux column will help to minimize loss of the distillate.

If a compound with a higher boiling point is added, the vapors of this liquid will displace the vapors of this small amount of compound with a lower boiling point. This compound with a higher boiling point is known as a Chaser.

6 0
3 years ago
starting with methane ,name all the steps and write the equations involved in tetrachlorination.Remember all arrows sharing move
anygoal [31]

Answer:

See Explanation and image attached

Explanation:

Methane is an alkane. The commonest chemical reaction that alkanes undergo is substitution. During a substitution reaction, one or more atoms of hydrogen is/are replaced in the alkane.

In methane, in the presence of sunlight and molecular chlorine gas, a homolytic fission of Cl2 occurs to yield chlorine radicals in an initiation step.

The propagation steps involve reaction of the methane with chlorine radicals. Certain intermediates continue to be formed along the way until the tetrachlorination product is finally obtained.

4 0
2 years ago
Why are alloys generally used to make everyday objects
dezoksy [38]
Chem bonds by exchanged charges create new characteristics as a result
4 0
3 years ago
A sample of gas is observed to effuse through a pourous barrier in 4.98 minutes. Under the same conditions, the same number of m
kogti [31]

Answer:

The molar mass of the unknown gas is \mathbf{ 51.865 \  g/mol}

Explanation:

Let assume that  the gas is  O2 gas

O2 gas is to effuse through a porous barrier in time t₁ = 4.98 minutes.

Under the same conditions;

the same number of moles of an unknown gas requires  time t₂  =  6.34 minutes to effuse through the same barrier.

From Graham's Law of Diffusion;

Graham's Law of Diffusion states that, at a constant temperature and pressure; the rate of diffusion of a gas is inversely proportional to the square root of its density.

i.e

R \  \alpha  \ \dfrac{1}{\sqrt{d}}

R = \dfrac{k}{d}  where K = constant

If we compare the rate o diffusion of two gases;

\dfrac{R_1}{R_2}= {\sqrt{\dfrac{d_2}{d_1}}

Since the density of a gas d is proportional to its relative molecular mass M. Then;

\dfrac{R_1}{R_2}= {\sqrt{\dfrac{M_2}{M_1}}

Rate is the reciprocal of time ; i.e

R = \dfrac{1}{t}

Thus; replacing the value of R into the above previous equation;we have:

\dfrac{R_1}{R_2}={\dfrac{t_2}{t_1}}

We can equally say:

{\dfrac{t_2}{t_1}}=  {\sqrt{\dfrac{M_2}{M_1}}

{\dfrac{6.34}{4.98}}=  {\sqrt{\dfrac{M_2}{32}}

M_2 = 32 \times ( \dfrac{6.34}{4.98})^2

M_2 = 32 \times ( 1.273092369)^2

M_2 = 32 \times 1.62076418

\mathbf{M_2 = 51.865 \  g/mol}

7 0
2 years ago
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