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kenny6666 [7]
3 years ago
5

In the presence of an emulsifying agent, a mixture of oil and water becomes a _____.

Chemistry
1 answer:
Alex Ar [27]3 years ago
7 0

Answer:

Colloidal dispersion or emulsion

Explanation:

The colloid of a liquid in liquid (both dispersed phase and dispersion medium are liquids) is known as emulsion or colloidal dispersion.

We know that oil and water are immiscible liquids. In order to make them miscible we have have add emulsifying agents.

An emulsifying agent has a long non polar hydrocarbon chain (in general) and a polar head.

For example salts of fatty acids.

The polar head is hydrophilic and non polar tail is hydrophobic.

It causes the miscibility of the two polar and non polar liquids

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A rectangular prism of volume 84 cm 3 has a mass of 760 g. What is the density of the rectangular prism? 5.8 g•cm 3 9.0 g/cm 3 6
Fiesta28 [93]

Answer:

9.0 g/cm³

Explanation:

Density can be computed with the formula:

D=\dfrac{M}{V}

Where:

D = Density

M = Mass

V = Volume

In your problem we are given:

84 cm³ = volume

760 g = mass

So we just plug in our given into the formula:

D=\dfrac{M}{V}

D=\dfrac{760g}{84cm^{3}}

D=9.05g/cm^{3}

The answer would then be:

9.0 g/cm³

3 0
3 years ago
100 points
Mariana [72]

Answer:

Where is the puzzle!??

I surely can help you

5 0
3 years ago
Read 2 more answers
A sample of hydrogen gas collected over water occupied 30.0 mL at 24 °C on a day when the atmospheric pressure was 736 Torr. Wha
givi [52]

Answer:0.026ml

Explanation:

Details are found in the image attached. We must subtract the saturated vapour pressure of hydrogen gas at the given temperature from the total pressure of the hydrogen gas collected over water to obtain the actual pressure of hydrogen gas and substitute the value obtained into the general gas equation. The dry hydrogen gas has no saturated vapour pressure hence the value is substituted as given. All temperatures must be converted to Kelvin before substitution.

4 0
3 years ago
6 × 10^9 mm = m. how to convert millimeters to m​
OLga [1]

Answer:

6x10^9x10^-3m=6x10^6m

Explanation:

3 0
3 years ago
indicate whether the entropy of the system increases or decreases. Mixing 10 mL of 90.0 °C water with 10 mL of 10 °C water. The
Ivanshal [37]

Answer:

When the water is mixed with water at lower temperature the effective temperature of the system (i.e the water at lower temperature) will increase, thereby increasing it's entropy

Explanation:

The answer that "the entropy will is increases" is correct as:

The water at 90° C i.e at higher temperature is mixed with the water at 10° C i.e the water at the lower temperature.

The water at lower temperature will have molecules with lower energy while the water with higher temperature will have molecules undergoing high thermal collisions. Thereby, when the water is mixed with water at lower temperature the effective temperature of the system (i.e the water at lower temperature) will increase, thereby increasing it's entropy.

Therefore, the answer is correct with respect to the water at lower temperature.

Meanwhile, for the water at higher temperature , the temperature of the system will decrease. Thus, the entropy of the water at higher level will decrease.

5 0
3 years ago
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