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Sauron [17]
3 years ago
13

Which statement accurately describes the reactants of a reaction? new substances that are present at the end of a reaction subst

ances that are used up in a reaction substances that do not participate in a reaction new substances formed in the reaction
Chemistry
2 answers:
ICE Princess25 [194]3 years ago
8 0

Answer:

C

Explanation:

took the test and got it correct

Jobisdone [24]3 years ago
3 0
Option (C) is the correct answer. In the chemical reaction, reactants are the starting elements or compounds which will chemically react and will form the products. Reactants are only present on the left hand side of the reaction and products are present on the right hand side of the reaction.
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One mole of ANY element contains the:
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What is the half-life of an isotope that decays to 12.5% of its original activity in 19.8 hours?
katen-ka-za [31]
x= x_{0}  e^{kt} ,where~ x ~is~ the ~ |amount\ of \material\ at\ any~~time~t

and~ x_{0} ~the~original~amount.
when~x=  \frac{12.5}{100} x_{0}  }= \frac{125}{1000}  x_{0}
\frac{x}{ x_{0} } = \frac{125}{1000}= \frac{1}{8}
when t=19.8 hrs,
x= x_{0}  e^{19.8 k}, 
 \frac{x}{ x_{0} } = e^{19.8 k}, 
 \frac{1}{8} = e^{19.8k} ,
ln \frac{1}{8} =19.8 k,

ln1-ln8=19.8k,
0-ln 2^{3} =19.8 k,
-3 ln2=19.8k
k= \frac{-3 ln2}{19.8} = \frac{- ln 2}{6.6}x= x_{0}  e^{ \frac{-ln2}{6.6}t } ,
 \frac{x}{ x_{0} } = e^{ \frac{- ln 2}{6.6}t } 
\frac{1}{2} = e^{ \frac{- ln2}{6.6}t } = \frac{1}{ e^{ \frac{ln 2}{6.6} t} } ,
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8 0
4 years ago
A human zygote has 46 chromosomes. This number of chromosomes represents what in a human cell?
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If the sperm carries a Y chromosome, it will result in a male. During fertilization, gametes from the sperm combine with gametes from the egg to form a zygote. The zygote contains two sets of 23 chromosomes, for the required 46.
3 0
3 years ago
You are given two aqueous solutions with different ionic solutes (Solution A and Solution B). What if you are told that Solution
klio [65]

Answer:

Yes, it is possible. Let us consider an example of two solutions, that is, solution A having 20 percent mass RbCl (rubidium chloride) and solution B is having 15 percent by mass NaCl or sodium chloride.  

It is found that solution A is having more concentration in comparison to solution B in terms of mass percent. The formula for mass percent is,  

% by mass = mass of solute/mass of solution * 100

Now the formula for molality is,  

Molality = weight of solute/molecular weight of solute * 1000/ weight of solvent in grams

Now molality of solution A is,  

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Now the molality of solution B is,  

m = 15/58.5 * 1000/85

m = 3.02

Therefore, in terms of molality, the solution B is having greater concentration (3.02) in comparison to solution A (2.07).

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