all of the above is the answer :)
Answer:
a) ΔGº= -49,9 KJ/mol = - 50 KJ/mol
b) The reaction goes to the right to formation of products
c) ΔG= 84,42 KJ/mol. The direction is to reactive, to the left
Explanation:
a) ΔGº= - RTLnKf
You need to convert Cº to K. 25ºC=298K
Then, ΔGº= - 3,814 J/molK * 298K* Ln(5.6 *10^8)= - 49906 J/mol = -49,9 KJ/mol = - 50 KJ/mol
b) The ΔGº < 0, that means the direct reaction is spontaneous when te reactive and products are in standard state. In other words the reaction goes to the right, to formation of products
c) The general ecuation for chemical reaction is aA + bB → cD + dD. Thus
ΔG=ΔGº + RTLn (([C]^c*[D]^d)/[A]^a*[B]^b)
In this case,
ΔG=ΔGº + RTLn ([Ni(NH3)62+] / [Ni2+]*[NH3]^6 )= 84417 J/mol =84,42 KJ/mol
ΔG >0 means the reaction isn't spontaneous in the direction of the products. Therefore the direction is to reactive, to the left
Answer:
Carbon, Hydrogen, Oxygen, Nitrogen, and Sulfur.
(Those are all the ones I know)
Answer:
91.2 nm
Explanation:
The Rydberg equation is given by the formula
1/ λ = Rh ( 1/ n₁² - 1/ n₂²)
where
λ is the wavelength
Rh is Rydberg constant
and n₁ and n₂ are the energy levels of the transion.
We can see from this equation that the wavelength is inversely proportional to the difference of the squares of the inverse of the quantum numbers n₁ and n₂. It follows then that the smallest wavelength will be given when the the transitions are between the greatest separation between n₁ and n₂ whicg occurs when n1= 1 and n₂= ∞ , that is the greater the separation in energy levels the shorter the wavelength.
Substituting for n₁ and n₂ and solving for λ :
1/λ = 1.0974 x 10⁷ m⁻¹ x ( 1/1² -1/ ∞²) = 1.0974 x 10⁷ m⁻¹ x ( 1/1² - 0) =
λ = 1/1.0974 x 10⁷ m = 9.1 x 10⁻8 m = 91.2 nm
