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otez555 [7]
3 years ago
7

In humans, genetic material in the cell is organized into

Chemistry
1 answer:
vladimir2022 [97]3 years ago
6 0
23 pairs of chromosomes, since there is 46 singular chromosomes.
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Metal in period 6 group 1
Nady [450]
The answer is ceslum
4 0
4 years ago
Which action is necessary for a solar eclipse to occur?​
Nat2105 [25]

Answer:

Moon has to be in-between the Earth and the Sun.

2. Moon's umbra should sweep your place.

3. Latitude and longitude of your place should be within the befitting limits.

6 0
3 years ago
Consider this initial-rate data at a certain temperature for the reaction described by N2O3(
Yuliya22 [10]

<span><span>N2</span><span>O3</span><span>(g)</span>→NO<span>(g)</span>+<span>NO2</span><span>(g)</span></span>

<span><span>[<span>N2</span><span>O3</span>]</span> Initial Rate</span>
<span>0.1 M     r<span>(t)</span>=0.66</span> M/s
<span>0.2 M     r<span>(t)</span>=1.32</span> M/s
<span>0.3 M     r<span>(t)</span>=1.98</span> M/s

We can have the relationship:

<span>(<span><span>[<span>N2</span><span>O3</span>]/</span><span><span>[<span>N2</span><span>O3</span>]</span>0</span></span>)^m</span>=<span><span>r<span>(t)/</span></span><span><span>r0</span><span>(t)
However,
</span></span></span>([N2O3]/[N2O3]0) = 2

Also, we assume m=1 which is the order of the reaction.

Thus, the relationship is simplified to,

r(t)/r0(t) = 2

r<span>(t)</span>=k<span>[<span>N2</span><span>O3</span>]</span>

0.66 <span>M/s=k×0.1 M</span>

<span>k=6.6</span> <span>s<span>−<span>1</span></span></span>

6 0
3 years ago
Read 2 more answers
A compound is broken down into 34.5 g of element a, 18.2 g of element b, and 2.6 g of element
Katena32 [7]
First, find the total mass.

34.5 g + 18.2 g + 2.6 g = 55.3 g

Divide the mass of each element by total mass.

34.5 g / 55.3 g = .62 x 100 = 62% element a

18.2 g / 55.3 = .33 x 100 = 33% element b

2.6 g / 55.3 = .047 x 100 = 4.7% element c

Hope I helped!


8 0
3 years ago
If it take 20 second for 200cm3 of H25 to diffuse through a porovs pot,hours,long will it take 400cm3 of NH3 of diffuse under th
trapecia [35]

Answer:

40 seconds chief just double it

Explanation:

5 0
3 years ago
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