Answer:
1) No shift
2) No shift
3) Leftward shift
4)Rightward sifht
Explanation:
1) 2) Adding N or Removing N in the equilibrium will produce No shift, because of its solid state, the N is not contemplated in the equilibrium equation:
3) Increasing the volume produces a decrase in the preassure due to the expansion of the gases. This will cause a leftward shift, because the system will try to increase the moles of gas and in consecuence of this, also increase the preassure.
4) Decreasing the volume has the opposite effect of the item 3): the preassure will increase and the system will consume moles of gas to decrease it, producing a rightward shift.
<span>When water decomposes into oxygen and hydrogen, the mass "Remains Constant" as according to Law of Conservation of mass, mass can neither be created not destroyed,.
In short, Your Answer would be Option A
Hope this helps!</span>
The rate of entropy change:
The rate of entropy change of the working fluid during the heat addition process is 3 kW/K
What is the Carnot cycle?
- The Carnot Cycle is a thermodynamic cycle made up of reversible isothermal expansion, adiabatic expansion, isothermal compression, and adiabatic compression processes in succession.
- The ratio of the heat absorbed to the temperature at which the heat was absorbed determines the change in entropy.
The entropy of a system:
The rate of heat addition is expressed as,
Q = 
The entropy of a system is a measure of how disorderly a system is getting. The rate of entropy generation during heat addition is,

Calculation:
<u>Given:</u>
= 400K
= 1600K
W = 3600 kW
Put all the values in the above equation, and we get,
=
= 3 kW/K
The rate of entropy change is 3 kW/K
Learn more about the Carnot cycle here,
brainly.com/question/13002075
#SPJ4
Molar mass Argon = 39.948 g/mol
1 mol ------ 39.948 g
mol ----- 20.0 g
mol = 20.0 * 1 / 39.948
= 0.5006 moles
1 mol --------------------- 22.4 L ( at STP )
0.5006 moles ------------- L
L = 0.5006 * 22.4
= 11.21 L
hope this helps!