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Inessa [10]
4 years ago
5

If light needs matter , how doe it move through space? this is my first question.

Physics
1 answer:
Assoli18 [71]4 years ago
7 0
Light is not matter. A photon is not matter because it has no mass. So rephrase your question...
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PLZ HELP
Sati [7]

Answer:

the index of refraction of the second medium is lower

Explanation:

take an exaple of a light ray from air to water that is optically denser the ray is refracted to the normal thus lowering its index of refraction

8 0
3 years ago
Read 2 more answers
1 A truck covers a distance of 580km in 7 hours - Calculate<br>the velocity in km/hr​
Digiron [165]

Answer:

82.86

Explanation:

to find velocity you displacement by time

3 0
3 years ago
A +5.00 pC charge is located on a sheet of paper.
emmainna [20.7K]

Answer:

a)    V = - x ( σ / 2ε₀)

c)  parallel to the flat sheet of paper

Explanation:

a) For this exercise we use the relationship between the electric field and the electric potential

          V = - ∫ E . dx        (1)

for which we need the electric field of the sheet of paper, for this we use Gauss's law. Let us use as a Gaussian surface a cylinder with faces parallel to the sheet

       Ф = ∫ E . dA = q_{int} /ε₀

the electric field lines are perpendicular to the sheet, therefore they are parallel to the normal of the area, which reduces the scalar product to the algebraic product

          E A = q_{int} /ε₀

area let's use the concept of density

        σ = q_{int}/ A

       q_{int} = σ A

          E = σ /ε₀

as the leaf emits bonnet towards both sides, for only one side the field must be

          E = σ / 2ε₀

         we substitute in equation 1 and integrate

      V = - σ x / 2ε₀  

       V = - x ( σ / 2ε₀)

if the area of ​​the sheeta is 100 cm² = 10⁻² m²

      V = - x  (10⁻²/(2 8.85 10⁻¹²) = - x  ( 5.6 10⁻¹⁰)

       

      x = 1 cm     V = -1   V

      x = 2cm     V = -2   V

This value is relative to the loaded sheet if we combine our reference system the values ​​are inverted

       V ’= V (inf) - V

       x = 1 V = 5

       x = 2 V = 4

       x = 3 V = 3

   

These surfaces are perpendicular to the electric field lines, so they are parallel to the sheet.

 

In the attachment we can see a schematic representation of the equipotential surfaces

b) From the equation we can see that the equipotential surfaces are parallel to the sheet and equally spaced

c) parallel to the flat sheet of paper

8 0
3 years ago
If a shuttle is orbiting a planet at a distance of 40 miles from the center of the planet, and is traveling at a rate of 500 mil
lawyer [7]

Answer:

Time taken, t = 30.15 minutes

Explanation:

It is given that,

Distance from the center of planet, r = 40 miles

Speed of the shuttle, v = 500 miles per hour

Let t is the time taken by it to complete  one full orbit. The displacement of the shuttle is,

d=2\pi r

d=2\pi \times 40

d = 251.32 miles

Now time can be calculated using the expression for the velocity as :

v=\dfrac{d}{t}

t=\dfrac{d}{v}

t=\dfrac{251.32\ miles}{500\ miles\ per\ hour}

t = 0.50264 hours

or

t = 30.15 minutes

So, the shuttle will take 30.15 minutes to complete one full orbit. Hence, this is the required solution.

7 0
3 years ago
Convert 89 degrees Fahrenheit to Celsius
777dan777 [17]
89 degrees Fahrenheit would be 31.7 degrees Celsius!
5 0
3 years ago
Read 2 more answers
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