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Tasya [4]
2 years ago
13

A race starts and finishes a race that is 50,000m. (30miles). The time is 23 minutes. The final velocity is 67m/s. What is the a

verage acceleration ?
Use acceleration formula
Physics
1 answer:
Serga [27]2 years ago
7 0

Answer:

a = 0.0505 [m/s^2]

Explanation:

In order to solve this formula we must use the following formula of kinematics.

x=(v_{o} *t)+(\frac{1}{2} )*a*t^{2}

where:

x = distance = 50000 [m]

Vo = initial velocity = 0

a = acceleration [m/s^2]

t = time = 23 [min] = 1380 [s]

Note: the positive sign in the above equation shows that the car accelerates.

50000 = (0*1380) + (0.5*a*1380^2)

a = 0.0525 [m/s^2]

But we can calculate the acceleration using the following formula:

v_{f} =v_{o} +a*t

where:

Vf = final velocity = 67 [m/s]

67 = 0 + (a*1380)

a = 0.0485 [m/s^2]

We can see that by means of kinematics and with the given values we can find two values of accelerations, however, we can determine the average acceleration, by means of the mathematical average.

a = (0.0485 + 0.0525) / 2

a = 0.0505 [m/s^2]

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A lab cart with a mass of 15 kg is moving with constant velocity, v, along a straight horizontal track. A student drops a 2 kg m
lbvjy [14]

The equation 15v_{i} + 2*0 = (15 + 2)v_{f} (option 3) represents the horizontal momentum of a 15 kg lab cart moving with a constant velocity, v, and that continues moving after a 2 kg object is dropped into it.  

The horizontal momentum is given by:

p_{i} = p_{f}

m_{1}v_{1}_{i} + m_{2}v_{2}_{i} = m_{1}v_{1}_{f} + m_{2}v_{2}_{f}

Where:

  • m₁: is the mass of the lab cart = 15 kg
  • m₂: is the <em>mass </em>of the object dropped = 2 kg
  • v_{1}_{i}: is the initial velocity of the<em> lab cart </em>
  • v_{2}_{i}: is the <em>initial velocit</em>y of the <em>object </em>= 0 (it is dropped)
  • v_{1}_{f}: is the final velocity of the<em> lab cart </em>
  • v_{2}_{f}: is the <em>final velocity</em> of the <em>object </em>

Then, the horizontal momentum is:

15v_{1}_{i} + 2*0 = 15v_{1}_{f} + 2v_{2}_{f}

When the object is dropped into the lab cart, the final velocity of the lab cart and the object <u>will be the same</u>, so:

15v_{1}_{i} + 2*0 = v_{f}(15 + 2)

Therefore, the equation 15v_{i} + 2*0 = (15 + 2)v_{f} represents the horizontal momentum (option 3).

Learn more about linear momentum here:

  • brainly.com/question/2141713?referrer=searchResults
  • brainly.com/question/2400186?referrer=searchResults

I hope it helps you!            

4 0
2 years ago
Vector sum of 15 m, East and 9 m, West is 24 m, East. True False
Firlakuza [10]

Answer:

False

Explanation:

Because when you go through east

( +x axis ) then you go to west ( -x axis )

You will subtract -9 from +15

it's become +6

( I talk about the displacement not distance) ( West = - East )

I hope that it's a clear ") .

7 0
3 years ago
Read 2 more answers
Alguien me ayuda con calculos estequiometricos?
ruslelena [56]

Answer:

SURE!!!...

But what to calculate!!!....

5 0
3 years ago
A small button placed on a horizontal rotating platform with diameter 0.320 m will revolve with the platform when it is brought
Otrada [13]

Answer:

0.2687 approximately 0.27

Explanation:

Diameter = 0.320

Speed = 40.0 rev/min

We are required to find coefficient of static friction between friction and button

The radius can be calculated as

0.320/2

= 0.160m

Then we have the rotational speed w = 40rev/min x 2pi/60

= 4.19 rad/s

umg = mrw²

u = mrw²/mg

u = rw²/g -------(1)

g = 9.8

When we put values into equation 1

0.150m x 4.19² / 9.8

= 0.150m x 17.5561 /9.8

= 0.2689

This is approximately 0.27

6 0
2 years ago
Please help soon!!!!
anyanavicka [17]
The Answer: Parallel
6 0
3 years ago
Read 2 more answers
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