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Tasya [4]
3 years ago
13

A race starts and finishes a race that is 50,000m. (30miles). The time is 23 minutes. The final velocity is 67m/s. What is the a

verage acceleration ?
Use acceleration formula
Physics
1 answer:
Serga [27]3 years ago
7 0

Answer:

a = 0.0505 [m/s^2]

Explanation:

In order to solve this formula we must use the following formula of kinematics.

x=(v_{o} *t)+(\frac{1}{2} )*a*t^{2}

where:

x = distance = 50000 [m]

Vo = initial velocity = 0

a = acceleration [m/s^2]

t = time = 23 [min] = 1380 [s]

Note: the positive sign in the above equation shows that the car accelerates.

50000 = (0*1380) + (0.5*a*1380^2)

a = 0.0525 [m/s^2]

But we can calculate the acceleration using the following formula:

v_{f} =v_{o} +a*t

where:

Vf = final velocity = 67 [m/s]

67 = 0 + (a*1380)

a = 0.0485 [m/s^2]

We can see that by means of kinematics and with the given values we can find two values of accelerations, however, we can determine the average acceleration, by means of the mathematical average.

a = (0.0485 + 0.0525) / 2

a = 0.0505 [m/s^2]

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Answer:

Solution:

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A woman is 160160cm tall. What is the minimum vertical length of a mirror in which she can see her entire body while standing up
kipiarov [429]

This question is incomplete, the complete question is;

A woman is 160cm tall. What is the minimum vertical length of a mirror in which she can see her entire body while standing upright.

Hint: Consider the ray diagram below, of the rays that enable her to see her feet and the top of her head.

Use what you know about the law of reflection, together with a bit geometry.

The missing Image is uploaded along this answer below.

Answer:

the minimum vertical length of a mirror in which she can see her entire body while standing upright is 80 cm

Explanation:

Given the data in the question and illustrated in the image below,

From image 2;

The distance from the woman's eyes to the top of her head is represented as b and a represent the distance from her eyes to her feet.

Therefore, since her height is 160 cm

a + b = 160 ------ let this be equation 1

i.e AD + DG = 160 cm

Now, from the same image 2, we will notice that triangle ABC and tringle CBD are similar, so

∠ABC = ∠CBD

AC = CD

since AD = a and AC + CD = A

AC = CD = a/2

Also, triangle DEF and FEG are si,ilar

∠DEF = ∠FEG

so

DF = FG

since DG = b and DF + FG = b

DF = b/2

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4 0
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Answer:

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This means that the wave will bend away from the normal. So the other correct option is

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