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4 years ago

How does flextape adhere under water?

Engineering

1 answer:

Katen [24]4 years ago

7 0

Answer:

It adhears well underwater.

Explanation:

Once you cut the tape and place it on the leak, it stops the water almost immediatly. It had a rubber backside so underwater it holds well.

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A large retail organization previously divided work among its four employee benefits staff into distinct specializations. One pe

denpristay [2]

Answer:

This job restructuring is an example of job enrichment.

Explanation:

Job enrichment is a motivational tool used by organizations to give employees greater satisfaction in their jobs, by giving them additional responsibilities previously reserved for higher-ranking positions.

8 0

3 years ago

A subsurface exploration report shows that the average water content of a fine-grained soil in a proposed borrow area is 22% and

Morgarella [4.7K]

Answer:

shrinkage ratio = 1.538

Explanation:

given data

water content = 22 %

dry density γ = 82 pcf

required dry density specified γ' = 96 pcf

required to produce = 50,000 yd³ = 50000 × 27 = 1350,000 ft³

solution

we get here first volume of borrow pit that is we know that

dry density ∝ $\frac{1}{volume}$

so $\frac{\gamma d}{\gamma 'd} = \frac{v'}{v}$

$\frac{82}{96} = \frac{1350000}{v}$

v = 1580487.8 ft³

v = 58536.58 yd³

so here

shrinkage ratio will be as

shrinkage ratio = $\frac{96}{62.4}$

shrinkage ratio = 1.538

6 0

3 years ago

Three spheres are subjected to a hydraulic stress. The pressure on spheres 1 and 2 is the same, and they are made of the same ma

r-ruslan [8.4K]

Answer:

"150000 N/m²" is the right approach.

Explanation:

According to the question, the pressure on the two spheres 1 and 2 is same.

Sphere 1 and 2:

Then,

⇒ $P_1=P_2$

⇒ $\frac{\Delta V_1}{V_1}=\frac{\Delta V_2}{V_2}$

and the bulk modulus be,

⇒ $B_1=B_2$

Sphere 3:

⇒ $\frac{\Delta V_3}{V_3} =\frac{\frac{\Delta V_1}{V_1} }{\frac{\Delta V_2}{V_2} } =1$

then,

⇒ $P_3=B\times \frac{\Delta V_3}{V_3}$

⇒ $=B\times 1$

⇒ $=150000\times 1$

⇒ $=150000 \ N/m^2$

5 0

3 years ago

Stainless steel ball bearings (rho = 8085 kg/m3 and cp = 0.480 kJ/kg·°C) having a diameter of 1.2 cm are to be quenched in water

sveticcg [70]

Answer:

$\dot Q = -2.341\,kJ$

Explanation:

The rate of heat transfer from the balls to the air is:

$\dot Q = \left[(800\,\frac{1}{min} )\cdot (\frac{1\,min}{60\,s} )\cdot(8085\,\frac{kg}{m^{3}})\cdot (\frac{4}{3}\pi )\cdot (6\times 10^{-3}\,m)^{3}\right]\cdot (0.480\,\frac{kJ}{kg\cdot ^{\textdegree}C} )\cdot (850\,^{\textdegree}C-900\,^{\textdegree}C)$ $\dot Q = -2.341\,kJ$

3 0

4 years ago

Read 2 more answers

Viscous effects are negligible outside of the hydrodynamic boundary layer. (3 points) a. True b. False

Valentin [98]

Answer:

I would say false but I am not for sure

8 0

3 years ago

How does flextape adhere under water?​

How does flextape adhere under water?