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lbvjy [14]
2 years ago
14

When bending metal, the material on the outside of the curve stretches while the material on the inside of the curve compresses.

That part of the material which is not affected by either stress is the g
Engineering
1 answer:
Nostrana [21]2 years ago
4 0

That part of the material which is not affected by either stress is the neutral line or axis.

<h3>What is the technique known as whilst you bend steel?</h3>

Sheet Metal Bending – Methods, Design Tips & K Factor. Bending is one of the maximum not unusual place sheet steel fabrication operations. Also referred to as press braking, flanging, die bending, folding and edging, this technique is used to deform a cloth to an angular shape. This is finished thru the utility of pressure on a workpiece.

The neutral axis is in which neither the fabric stretches nor is compressed. Hence, the duration of the nuetral axis lives the identical earlier than and after the bending operation.

Read more about the bending :

brainly.com/question/13637124

#SPJ1

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A cylindrical metal specimen having an original diameter of 12.8 mm and gauge length of 50.80 mm is pulled in tension until frac
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Answer:

%Reduction in area = 73.41%

%Reduction in elongation = 42.20%

Explanation:

Given

Original diameter = 12.8 mm

Gauge length = 50.80mm

Diameter at the point of fracture = 6.60 mm (0.260 in.)

Fractured gauge length = 72.14 mm.

%Reduction in Area is given as:

((do/2)² - (d1/2)²)/(do/2)²

Calculating percent reduction in area

do = 12.8mm, d1 = 6.6mm

So,

%RA = ((12.8/2)² - 6.6/2)²)/(12.8/2)²

%RA = 0.734130859375

%RA = 73.41%

Calculating percent reduction in elongation

%Reduction in elongation is given as:

((do) - (d1))/(d1)

do = 72.14mm, d1 = 50.80mm

So,

%RA = ((72.24) - (50.80))/(50.80)

%RA = 0.422047244094488

%RA = 42.20%

3 0
4 years ago
A gas stream flowing at 1000 cfm with a particulate loading of 400 gr/ft3 discharges from a certain industrial plant through an
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<u>Solution and Explanation:</u>

Volume of gas stream = 1000 cfm (Cubic Feet per Minute)

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Total weight of particulate matter = 1000 \mathrm{cfm} \times 400 \mathrm{gr} / \mathrm{tt} 3 \times .000142857 \mathrm{lb} / \mathrm{ft} 3 \times 60=3428.568 \mathrm{lb} / \mathrm{hr}

Cyclone is to 80 % efficient

So particulate remaining = 0.20 \times 3428.568 \mathrm{lb} / \mathrm{hr}=685.7136

emissions from this stack be limited to = 10.0 lb/hr

Particles to be remaining after wet scrubber = 10.0 lb/hr

So particles to be removed = 685.7136- 10 = 675.7136

Efficiency = output multiply with 100/input = 98.542 %

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A spud wrench and pipe is for install pipes
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Answer:

<u><em>≡</em></u>

Explanation:

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