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horsena [70]
4 years ago
9

The calcium carbonate found in limestone was originally extracted from _______.

Chemistry
2 answers:
Iteru [2.4K]4 years ago
5 0
The calcium carbonate found in limestone was originally extracted from A. SEAWATER.

Limestone is a sedimentary rock. It was formed from small rock or stone particles that have been compacted by pressure. It can be formed either by evaporation or with the help of living organisms.

Calcium carbonate in seawater are used by ocean-dwelling organisms to create their shells and bones; like corals, clams, oysters. When these organism die, their shells and bones are broken down by the waves and settle on the ocean floor where the pressure of the ocean water drives these sediments together to create limestone.

Limestone is created through evaporation. When water containing calcium carbonate evaporates it leaves behind the sediment deposit which in turn becomes limestone after being subjected to the water pressure.
Soloha48 [4]4 years ago
3 0

Answer:

Awnser is A

Explanation: just took the test

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Sometimes you are given a measured amount of two or more reactants and asked how much product can be formed. Explain what steps
Westkost [7]

Explanation:

To solve this problem, follow these steps;

  • Obtain a balanced equation of the reaction and familiarize with the reactants and products.
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  • From the number of moles, determine the limiting reactant.
  • The limiting reactant is the one given in short supply.
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  • Compare the moles of this specie to that of the products using the balanced equation.
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4 years ago
If a positively charges object is brought near the hook what happens
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Answer:i think there is a spark

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6 0
3 years ago
What volume of a 0.2089 M KI solution contains enough KI to react exactly with the Cu(NO3)2 in 40.88 mL of a 0.3842 M solution o
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Explanation:

As molarity is the number of moles placed in a liter of solution. Therefore, no. of mole = Molarity × volume of solution in liter

Hence, moles of Cu(NO_{3})_{2} will be calculated as follows.

No. of mole of Cu(NO_{3})_{2} = 0.3842 M \times 0.04388 L = 0.0168 mole

According to the given reaction, 2 mole of Cu(NO_{3})_{2} react with 4 mole of KI.

Therefore, for 0.0168 mole amount of Cu(NO_{3})_{2} required will be as follows.

Cu(NO_{3})_{2} = 0.0168 \times \frac{4}{2}

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Hence, volume of KI required will be calculated as follows.

               Volume = \frac{\text{no. of moles}}{Molarity}

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                           = 0.1614 liter

                            = 161.4 ml            (as 1 L = 1000 mL)

Thus, we can conclude that 161.4 ml  volume of a 0.2089 M KI is required for the given situation.

5 0
4 years ago
A sample of propane (C3H8) is placed in a closed vessel together with an amount of O2 that is 3 times the amount needed to compl
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Answer:

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final partial pressure of O₂ = 5 atm * 10/17 = 2.942 atm

final partial pressure of CO₂ = 5 atm * 3/17 = 0.882 atm

final partial pressure of H₂O = 5 atm * 1/17 = 1.176 atm

4 0
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