Question

A person of Mass 50kg is on a swing which has the speed 10m,/s at the lowest point of the motion the ropes of the swing are 2.5m long.find the tension in the ropes​

Answer 1

Answer:

T  =  2490 newton

Explanation:

Given that,

Mass of a person, m = 50 Kg

Speed of the swing at the lowest point, v = 10 m/s

Length of the rope, r = 2.5 m

Tension formula is given by

                            T = mg + ma  N

where,              T - Tension in the string

                         m - mass of the body

                         g - acceleration due to gravity

                          a - acceleration of the body

Since the person is swinging, the acceleration of the body is given by

                          a = v²/r m/s²

                             = 10/2.5  m/s²

                          a = 40 m/s²

Substituting in T

                   T  =  50 Kg x 9.8 m/s²  + 50 Kg X 40 m/s²

                       = 490 + 2000 Kg m/s²

                   T  =  2490 newton

Therefore the tension in the rope is 2490 newton