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2 years ago

Convert 5280 feet to furlongs

1 answer:

soldier1979 [14.2K]2 years ago

8 0

5,280 feet = 1 mile
1 furlong = 660 feet = 220 yards = 1/8 mile
5,280 feet = 8 furlongs

You can see how lucky we are to be able to stick with
our familiar units of measure, instead of being forced
to change to the confusing metric system.

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How can you demonstrate that charged objects exert forces, both attractive and repulsive

Tcecarenko [31]

If it attractive it has opposite pole and if it repulsive it has same pole

8 0

3 years ago

A Block slides down an incline that makes an angle of 30? with the horizontal direction. The coefficient of kinetic friction bet

astraxan [27]

Answer:

Acceleration = 2.35 m/ $s^{2}$

Speed = 8.67 m/s

Explanation:

The coefficient of friction , u =0.3

The angle of incline = 30°

The two forces acting on block are weight and friction.

weight along the incline = mg cos60° = $\frac{mg}{2}$ = 0.5 mg

Friction along incline = umg cos30° = mg $0.3\times \frac{\sqrt{3}}{2}$

Friction along incline = 0.26 mg

Net force acting on the weight = (0.5 - 0.26) mg = 0.24 mg

Acceleration = $\frac{net force}{mass}$ = 0.24 g = 2.35 m/ $s^{2}$

The height of incline = 8 m

Length of the inclined edge = 16 m

$v^{2}=u^{2}+2as$

$v^{2}= 2\times 0.24 \times 9.8\times 16$

v= 8.67 m/s

5 0

3 years ago

A __________ provides a visual summary of the improvements that a data mining project provides on a binary classification proble

babymother [125]

Answer:

Option (B)

Explanation:

A lift chart usually refers to a graphical representation that is mainly used in order to improve the drawbacks of a mining model by making a comparison with any random guess, and also helps in determining the changes that occur in terms of lift scores.

It describes the binary classification of the problems associated with the mining activity. This type of chart is commonly used to differentiate the lift scores for a variety of models, and picking the best one out of all.

Thus, the correct answer is option (B).

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3 years ago

If the crate shown here is moving at a constant speed in a straight line and the force applied is 310 N, what is the magnitude o

larisa86 [58]

Answer:

$f_k = 310N$

the answer is A.

Explanation:

Using the laws of newton:

∑F = ma

where ∑F is the sumatory of forces acting in the system, m the mass and a the acelertion of the system.

Then, if the block is moving with constant velocity, its aceleration is equal to 0, so:

∑F = m(0)

∑F = 0

It means that:

F - $f_k$ = 0

where F is the force applied and $f_k$ is the friction force. Replacing the value of F, we get:

310N - $f_k$ = 0

Finally, solving for $f_k$ :

$f_k = 310N$

8 0

3 years ago

All objects near the earths surface - regardless of size and weight - hhave the same force of gravityvacting on them.

masya89 [10]

Answer:

B. False

Explanation:

Not all objects near the earths surface - regardless of size and weight - have the same force of gravity on them.

4 0

3 years ago