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grigory [225]
3 years ago
13

Consider shining a laser through a small circular hole. The resulting diffraction pattern will look like a bullseye - a series o

f bright and dark concentric circular rings with a large bright circle in the middle. Now, you stretch the circular hole into a horizontal oval (the horizontal length is larger than the vertical length) and shine the same laser through the new hole. Which is true about the resulting diffraction pattern compared to the original pattern?
O The diffraction pattern will remain a circular bullseye, but the rings will be closer together
O The diffraction pattern will change to resemble a series of concentric oval rings with the long dimension vertical
O The diffraction pattern will change to resemble a series of concentric oval rings with the long dimension horizontal
O The diffraction pattern will remain unchanged
Physics
1 answer:
jeka57 [31]3 years ago
6 0
Hey, good morning. I hope u have a wonderful day doing ur work :)
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State and explain the principle of superposition of electrostatic force​
ella [17]

Answer:

The principle of superposition states that when a number of charges are interacting, the net electrostatic force a given charge is the vector sum of the forces exerted on it due to all other charges. The force between two charges is not affected by the presence of other charges.

8 0
3 years ago
A car slows down from 21 m/s to rest in a distance of 63m. Assuming the car has a constant acceleration, calculate the time it t
vladimir2022 [97]

Answer:

-3.5 m/s²

Explanation:

  • Initial Velocity = 21m /s
  • Final velocity = 0m/s
  • Distance = 63 m .
  • Acclⁿ = ?

<u>We </u><u>know</u><u> </u><u>that</u><u> </u><u>:</u><u>-</u><u> </u>

\longrightarrow Stopping distance = u²/2(-a)

\longrightarrow 63m = (21m/s)² / -2a

\longrightarrow a = - 21 * 21 / 63 * 2 m/s²

\longrightarrow a = - 3.5 m/s²

<em>*</em><em>*</em><em>Edits</em><em> </em><em>are</em><em> </em><em>welcomed</em><em>*</em><em>*</em>

5 0
3 years ago
A 0.250 kg block attached to a light spring oscillates on a frictionless, horizontal table. The oscillation amplitude is A = 0.1
bulgar [2K]

The spring constant, k will be 18 N/m.The ratio of force to one unit of displaced length is known as the spring constant.

<h3>What is the spring constant?</h3>

Spring constant is defined as the ratio of force per unit displaced length.

Given data;

Mass of  block,m=0.250 k

Amplitude,A = 0.125 m

Velocity,V=3.00 m/

Spring constant,K=?

The formula for the spring constant when the spring is oscillate at the given amplitude A:

\rm K = \frac{V_{max}^2 m}{A} \\\\  K = \frac{3.0 \times 0.250}{0.125} \\\\ K=18 \ N/m

Hence, the spring constant, k will be 18 N/m

To learn more about the spring constant, refer:

brainly.com/question/4291098

#SPJ1

8 0
2 years ago
A water bug is suspended on the surface of a pond by surface tension (water does not wet the legs). The bug has six leg, and eac
Crazy boy [7]

Answer:

m = 2.2 x 10⁻⁴ kg = 0.22 g

Explanation:

The surface tension of water is 0.072 N/m. So in order for the bug to avoid sinking, its weight per unit length of contact must be no more than the surface tension of water. Therefore,

Weight\ of bug\ per\ unit\ length = Surface\ Tension\ of\ Water\\\frac{mg}{L} = Surface\ Tension\ of Water\\m = \frac{(Surface\ Tension\ of\ Water)(L)}{g}

where,

m = mass of bug = ?

g = acceleration due to gravity = 9.81 m/s²

L = Contact length = (contact length of each leg)(No. of Legs) = (5 mm)(6)

L = 30 mm = 0.03 m

Therefore,

m = \frac{(0.072\ N/m)(0.03\ m)}{9.81\ m/s^{2}} \\

<u>m = 2.2 x 10⁻⁴ kg = 0.22 g</u>

8 0
3 years ago
Based on Newtons law of universal gravitation, complete the following table.
madam [21]
Gravity increases as mass increases.

Gravity decreases when distance decreases

I hope I help.
5 0
3 years ago
Read 2 more answers
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