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grigory [225]
3 years ago
13

Consider shining a laser through a small circular hole. The resulting diffraction pattern will look like a bullseye - a series o

f bright and dark concentric circular rings with a large bright circle in the middle. Now, you stretch the circular hole into a horizontal oval (the horizontal length is larger than the vertical length) and shine the same laser through the new hole. Which is true about the resulting diffraction pattern compared to the original pattern?
O The diffraction pattern will remain a circular bullseye, but the rings will be closer together
O The diffraction pattern will change to resemble a series of concentric oval rings with the long dimension vertical
O The diffraction pattern will change to resemble a series of concentric oval rings with the long dimension horizontal
O The diffraction pattern will remain unchanged
Physics
1 answer:
jeka57 [31]3 years ago
6 0
Hey, good morning. I hope u have a wonderful day doing ur work :)
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A car drives at a constant speed of 21 m/s around a circle with radius 100 m. What is the centripetal acceleration of the car?
Sauron [17]

If you look below, we are using the centripetal acceleration formula.  You just need to plug your numbers in and it should work!A_c = \frac{v^2}{r} \\A_c=\frac{21^2}{100} \\A_c=\frac{441}{100} \\A_c= 4.41m/s/s

6 0
3 years ago
A 93.5 kg snowboarder starts from rest and goes down a 60 degree slope with a 45.7 m height to a rough horizontal surface that i
frosja888 [35]

Answer:

a. 29.9 m/s, b. 29.6 m/s, c. 44.7 m

Explanation:

This can be answered with either force analysis and kinematics, or work and energy.

a) Using force analysis, we can draw a free body diagram for the snowboarder.  There are two forces: normal force perpendicular to the slope and gravity down.

Sum of the forces parallel to the slope:

∑F = ma

mg sin θ = ma

a = g sin θ

Therefore, the velocity at the bottom is:

v² = v₀² + 2a(x - x₀)

v² = (0)² + 2(9.8 sin 60°) (45.7 / sin 60° - 0)

v = 29.9 m/s

Alternatively, using energy:

PE = KE

mgh = 1/2 mv²

v = √(2gh)

v = √(2×9.8×45.7)

v = 29.9 m/s

b) Drawing a free body diagram, there are three forces on the snowboarder.  Normal force up, gravity down, and friction to the left.

Sum of the forces in the y direction:

∑F = ma

N - mg = 0

N = mg

Sum of the forces in the x direction:

∑F = ma

-F = ma

-Nμ = ma

-mgμ = ma

a = -gμ

Therefore, the snowboarder's final speed is:

v² = v₀² + 2a(x - x₀)

v² = (29.9)² + 2(-9.8×.102) (10 - 0)

v = 29.6 m/s

Using energy instead:

KE = KE + W

1/2 mv² = 1/2 mv² + F d

1/2 mv² = 1/2 mv² + mgμ d

1/2 v² = 1/2 v² + gμ d

1/2 (29.9)² = 1/2 v² + (9.8)(0.102)(10)

v = 29.6 m/s

c) This is the same as part a, but this time, the weight component parallel to the incline is pointing left.

∑F = ma

-mg sin θ = ma

a = -g sin θ

Therefore, the final height reached is:

v² = v₀² + 2a(x - x₀)

(0)² = (29.6)² + 2(-9.8 sin 30°) (h / sin 30° - 0)

h = 44.7 m

Using energy:

KE = PE

1/2 mv² = mgh

h = v² / (2g)

h = (29.6)² / (2×9.8)

h = 44.7 m

3 0
4 years ago
Determine whether each of the following combinations of forces can be in equilibrium if their directions
lesya692 [45]

Answer:

I think it is a or c hope this helps

6 0
3 years ago
8 N to the left , and 4 N to the right. Find the net force. Is this balanced?
alukav5142 [94]

Explanation:

12N by first law of newton is net force after colloision

7 0
2 years ago
Velocity is a: a) Fundamental quantity b) MKS system c) Standard system d) Derived quantity​
Naya [18.7K]

Velocity is a derived quantity, which is derived from two fundamental quantities ilength ( displacement ) and time

it can be depicted as :

  • \boxed{ \boxed{velocity =  \dfrac{displacement}{time} }}

4 0
3 years ago
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