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grigory [225]
2 years ago
13

Consider shining a laser through a small circular hole. The resulting diffraction pattern will look like a bullseye - a series o

f bright and dark concentric circular rings with a large bright circle in the middle. Now, you stretch the circular hole into a horizontal oval (the horizontal length is larger than the vertical length) and shine the same laser through the new hole. Which is true about the resulting diffraction pattern compared to the original pattern?
O The diffraction pattern will remain a circular bullseye, but the rings will be closer together
O The diffraction pattern will change to resemble a series of concentric oval rings with the long dimension vertical
O The diffraction pattern will change to resemble a series of concentric oval rings with the long dimension horizontal
O The diffraction pattern will remain unchanged
Physics
1 answer:
jeka57 [31]2 years ago
6 0
Hey, good morning. I hope u have a wonderful day doing ur work :)
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2 years ago
A bullet of mass 11 g strikes a ballistic pendulum of mass 1.9 kg. The center of mass of the pendulum rises a vertical distance
Ymorist [56]

Answer:

The bullet's initial speed is 243.21 m/s.

Explanation:

Given that,

Mass of the bullet, m_b=11\ g=0.011\ kg

Mass of the pendulum, m_p=19\ kg

The center of mass of the pendulum rises a vertical distance of 10 cm.

We need to find the bullet's initial speed if it is assumed that the bullet remains embedded in the pendulum. Let it is v. In this case, the energy of the system remains conserved. The kinetic energy of the bullet gets converted to potential energy for the whole system. So,

\dfrac{1}{2}(m_b+m_p)V^2 =(m_b+m_p)gh\\\\V=\sqrt{2gh} \ .................(1)

V is the speed of the bullet and pendulum at the time of collision

Now using conservation of momentum as :

m_bv=(m_p+m_b)V

Put the value of V from equation (1) in above equation as :

v=\dfrac{(m_p+m_b)}{m_b}\sqrt{2gh} \\\\v=\dfrac{(1.9+0.011)}{0.011}\sqrt{2\times 9.8\times 0.1}\\\\v=243.21\ m/s

So, the bullet's initial speed is 243.21 m/s.

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7. When initially-unpolarized light passes through three polarizing filters, each oriented at 45 degree angles from the precedin
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Answer:

Explanation:

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After second filter , the intensity  will be  I₀ / 2 x cos²45 =  I₀ / 4

After third filter , the intensity will be I₀ / 4  x cos²45 = I₀ / 8 .

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1 / 8 the of initial light passes through the last filter .

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3 years ago
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Answer:

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