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grigory [225]
2 years ago
13

Consider shining a laser through a small circular hole. The resulting diffraction pattern will look like a bullseye - a series o

f bright and dark concentric circular rings with a large bright circle in the middle. Now, you stretch the circular hole into a horizontal oval (the horizontal length is larger than the vertical length) and shine the same laser through the new hole. Which is true about the resulting diffraction pattern compared to the original pattern?
O The diffraction pattern will remain a circular bullseye, but the rings will be closer together
O The diffraction pattern will change to resemble a series of concentric oval rings with the long dimension vertical
O The diffraction pattern will change to resemble a series of concentric oval rings with the long dimension horizontal
O The diffraction pattern will remain unchanged
Physics
1 answer:
jeka57 [31]2 years ago
6 0
Hey, good morning. I hope u have a wonderful day doing ur work :)
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Alice and Tom dive from an overhang into the lake below. Tom simply drops straight down from the edge, but Alice takes a running
crimeas [40]

Answer:c

Explanation:

Given

Alice launches with horizontal velocity u=25\ m/s

Tom simply drops straight down from the edge

Time taken by both the person is same as they have same initial vertical velocity i.e. zero so the time taken to reach the ground is zero.

Although Alice will travel more horizontal distance compared to Tom.

Thus option c is correct

3 0
3 years ago
Why are heat transfers associated with phase changes known as latent or "hidden" heats?
pshichka [43]
The best and most correct answer among the choices provided by your question is the first choice or letter A.

Heat transfers associated with phase changes known as latent or "hidden" heats because h<span>eat absorbed or released in a phase change is measured in kJ while temperature is measured in °C.</span>


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
4 0
3 years ago
A 0.3-kg object connected to a light spring with a force constant of 19.3 N/m oscillates on a frictionless horizontal surface. A
Ghella [55]

The total work <em>W</em> done by the spring on the object as it pushes the object from 6 cm from equilibrium to 1.9 cm from equilibrium is

<em>W</em> = 1/2 (19.3 N/m) ((0.060 m)² - (0.019 m)²) ≈ 0.031 J

That is,

• the spring would perform 1/2 (19.3 N/m) (0.060 m)² ≈ 0.035 J by pushing the object from the 6 cm position to the equilibrium point

• the spring would perform 1/2 (19.3 N/m) (0.019 m)² ≈ 0.0035 J by pushing the object from the 1.9 cm position to equilbrium

so the work done in pushing the object from the 6 cm position to the 1.9 cm position is the difference between these.

By the work-energy theorem,

<em>W</em> = ∆<em>K</em> = <em>K</em>

where <em>K</em> is the kinetic energy of the object at the 1.9 cm position. Initial kinetic energy is zero because the object starts at rest. So

<em>W</em> = 1/2 <em>mv</em> ²

where <em>m</em> is the mass of the object and <em>v</em> is the speed you want to find. Solving for <em>v</em>, you get

<em>v</em> = √(2<em>W</em>/<em>m</em>) ≈ 0.46 m/s

8 0
3 years ago
Can someone help quickly please and thank you
Sergio039 [100]

Answer:

I think D??

Explanation:

8 0
2 years ago
Lonnie pitches a baseball of mass 0.20 kg. The ball arrives at home plate with a speed of 40 m/s and is batted straight back to
suter [353]

Answer:

B) 20N.s is the correct answer

Explanation:

The formula for the impulse is given as:

Impulse = change in momentum

Impulse = mass × change in speed

Impulse = m × ΔV

Given:

initial speed  = 40m/s

Final speed = -60 m/s (Since the the ball will now move in the opposite direction after hitting the bat, the speed is negative)

mass = 0.20 kg

Thus, we have

Impulse = 0.20 × (40m/s - (-60)m/s)

Impulse = 0.20 × 100 = 20 kg-m/s or 20 N.s

4 0
3 years ago
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