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uysha [10]
3 years ago
9

algunas fabricas de balones de futbol ubicadas en la costa inflan los balones que van a ser vendidos en ciudades como pasto,tunj

a o bogota por debajo de su capacidad normal y, cuando los balones llegan a los estudiantes de las tiendas en estas ciudades, se encuentran firmes ¿por que crees que sucede esto? por favor tengo que hacer esta pregunta para hoy si plis
Physics
1 answer:
solmaris [256]3 years ago
7 0

Answer:

Debido al cambio de volumen del gas dentro de la bola cuando se somete a una disminución de la presión y un aumento de la temperatura de la atmósfera.

Explanation:

La ubicación de las fábricas que fabrican las bolas que se encuentra en la costa como se indica en la pregunta es a baja altitud y una región más fría donde la presión atmosférica es más alta

Por lo tanto, la presión en la costa = p₁

La temperatura en la costa = T₁

El volumen de la pelota en la costa = V₁

Las condiciones en una ciudad con mayor altitud y temperatura tienen mayor presión atmosférica y temperatura de la siguiente manera;

La presión en la ciudad = p₂ <p₁

La temperatura en la ciudad = T₂> T₁

El volumen de la pelota en la costa = V₂

Por la ley de gas combinada de tenemos;

\dfrac{p_1 \times V_1}{T_1} = \dfrac{p_2 \times V_2}{T_2}

Allí el volumen de la pelota en la ciudad estará dado por la relación;

V_2 = V_1 \times \dfrac{p_1 }{P_2} \times  \dfrac{ T_2}{T_1 }

Dado que p₁> p₂ y T₂> T₁, entonces p₁/p₂> 1 y T₂/T₁> 1 y tenemos;

V₂ = V₁ × p₁/p₂ × T₂/T₁ = V₁ × X, donde X = p₁/p₂ × T₂/T₁> 1

V₂ = V₁ × X (> 1)

Por lo tanto, V₂> V₁ y el volumen ocupado por el gas aumenta cuando la pelota llega a la ciudad y la pelota está más firme.

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A 45 kg wagon is being pulled with a rope that makes an angle of 38 degrees with the horizontal. The applied force is 410 N and
mel-nik [20]

Answer:

7.35m/s²

Explanation:

From the question we are not told what to find but we can as well find the acceleration of the wagon.

According to newton second law of motion

\sum F_x = ma_x\\Fm - Ff = ma_x\\Fm - \mu R = ma_x\\Fm- \mu mg = ma_x\\

Fm is the moving force = 410N

\mu is the coefficient of friction = 0.18

m is the mass = 45kg

g is the acceleration dur to gravity = 9.8m/s²

a is the acceleration of the wagon

Substitute the given data into the equation ang get ax

Fm- \mu mg = ma_x\\410 - (0.18)(9.8)(45) = 45a_x\\410 - 79.38 = 45a_x\\330.62 = 45a_x\\a_x = 330.62/45\\a_x = 7.35m/s^2\\

Hence the acceleration of the wagon is 7.35m/s²

8 0
3 years ago
An astronaut orbits planet Y in her spaceship. To remain in orbit at 410km above the planet's center, she maintains a speed of 6
choli [55]
Formula for orbital speed, v =  √(GM/R)

Where G is the universal gravitational constant, M = Central Mass,

R = Distance between centers of Mass.

Given.  v = 68 m/s, M = ? , R = 410 km = 410000 m., G = 6.674 * 10⁻¹¹ Nm²/kg²

68 = √(GM/R)

68 = √(6.674 * 10⁻¹¹ * M/410000)

68² =  (6.674 * 10⁻¹¹ * M)/410000

(68²  * 410000) / 6.674 * 10⁻¹¹    = M

2.84 × 10¹⁹    = M

Mass of Planet Y =  2.84 × 10¹⁹ kg
3 0
3 years ago
Radio waves travel 300,000,000 m/s. The frequency is 101,700,000. ehats the wavelength​
Nesterboy [21]

Answer:

we have formula of frequency :

frequency(f)= speed of sound(c)/wavelength(λ)

for wavelength we swipe it with frequency as follows

λ=c/f

λ=300,000,000/101,700,000

λ=2.949

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3 years ago
Each of the colors of light in the visible light spectrum has...
lara31 [8.8K]
The answer is d that might help you
7 0
3 years ago
8. A 40.0kg block of metal is suspended from a scale and is immersed in water. The dimensions of the block are 12.0cm x 10.0cm x
Alja [10]

Answer:

a.1017.9N

b.1029.7N

c.T=380.6N

d.11.8 N

Explanation:

(a) The absolute pressure at the level of the top of the block is

Po=atmospheric pressure

g=gravity

h1=height

rh0=density of water

P1=Po+rho*g*h1

1.013*10^5+1000(9.81)(0.05)

1.0179*10^5Pa

at the level of the bottom of the block we have

P2=Po+rho*g*h2

1.013*10^5+1000(9.81)(0.17)

1.0297* 10^5 Pa

the downward force exerted on the top by the water is

Ftop=P*A== × = 1.0179* 10^5* 0.100

= 1017.9 N

and the upward force the water exerts on the bottom of the block , which is the buoyant force

Fbot== × = 1.0297 10^5 * 0.100 m

= 1029.7 N

(b) The scale reading is the tension, T, in the cord supporting the block.

if the block is at equilibrium, then sum of vertical forces

EFy=T+Fbot-Ftop-mg=0

T=mg+Ftop-Fbot

T=40*9.81-(1029.7-1017.9)

T=380.6N

(c)  Archimedes principle state that, the buoyant force on the block equals the weight of the displaced water. Thus,

Buoyant force=rho *g*h

= = 1000* 0.100^2 * 0.120 m *9.80 m s=11.8 N

from the answer a Ftop-Fbot

1029.7-1017.9=11.8N, the same as the buoyant force

5 0
3 years ago
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